Answer:
The length of PQ is <u>18</u> feet.
The length of PR is <u>18</u> feet.
The length of QR is <u>24</u> feet.
Step-by-step explanation:
A way to set an equation up for this problem is:
where x is the three lengths of the isosceles triangle, but the base QR is 4/3 the length of the other two congruent sides, length PQ and PR. The 60 represents the total length of the perimeter.
Then, solve for x from the equation, and you’ll get x=18. But your not done yet. Since the variable x in the equation stands for the sides of the isosceles triangle, so plug 18 into the equation and it should look like this:
Don’t solve the whole equation, just solve the 
part of the equation, which is equal to 24. So the final equation is this:
Conclusion: 24 is the length of QR, and 18 is the length of PQ and PR. And they all equal 60, which is the perimeter. This is very true because the length of PQ and PR are the same (length 18), since it’s an isosceles triangle, and the length of QR is 4/3 the length of PQ and PR (4/3 of 18= 24).
Sorry for the long explanation.
But hope this helps and answers your question :)
Answer:
3347000 cm is 33.47 km to cm
3347000/64=
401.92 is the circumference
since it is pi * d
do 3347000/401.92
8327.52786624 round to
8327 full revolutions
K=19 which would leave the equation 181=181. The first step to solving this is subtracting 9k from each side.
after you do that it should be k-9=10
now you add 9 to both sides leave k=19. plug k into the equation and get 181=181
Answer:
37
Step-by-step explanation:
tan(theta)=perpendicular/base
tan(theta)=3/4
theta=arctan(3/4)=37
Answer:
a) integral = 24.72
b) |Error| ≤ 0.4267
Step-by-step explanation:
a)
The integral:
can be approximated with the midpoint rule, as follows:
6.7*(0.8 - 0.0) + 8.9*(1.6 - 0.8) + 6.9*(2.4-1.6) + 8.4*(3.2 - 2.4) = 24.72
(that is, all the intervals are 0.8 units length and f(x) is evaluated in the midpoint of the interval)
b)The error bound for the midpoint rule with <em>n</em> points is:
|Error| ≤ K*(b - a)^3/(24*n^2)
where <em>b</em> and are the limits of integration of the integral and K = max |f''(x)|
Given that -5 ≤ f''(x) ≤ 1, then K = 5. Replacing into the equation:
|Error| ≤ 5*(3.2 - 0)^3/(24*4^2) = 0.4267
