The length of the shortest side of the hexagon is; 41.833 inches
<h3>How to find the perimeter of a Polygon?</h3>
Let the length of the shortest side of the hexagon be x. Now, a hexagon has six sides and if the next side is 10 inches longer than the previous side, then the length of the six sides are;
x, x + 10, x + 20, x + 30, x + 40, x + 50
Perimeter is given as 401 inches. Thus;
x + x + 10 + x + 20 + x + 30 + x + 40 + x + 50 = 401
6x + 150 = 401
6x = 401 - 150
6x = 251
x = 251/6
x = 41.833 inches
Read more about Polygon Perimeter at; brainly.com/question/14490532
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I would suggest factoring using the grouping method. The answer I got was (2n-1)(n+2)
Answer:
(2x-9)(2x+9)
Step-by-step explanation:
This is a difference of squares because it can be written as (2x)^2-9^2
The formula for factoring a difference of squares is a^2-b^2=(a-b)(a+b)
So replace a with 2x and b with 9 giving us
4x^2-81=(2x-9)(2x+9)
A is the 4
B is the 5
and C is also 4.
A is always the number in front of x^2. B is always the number i front of the normal x, and C is the number that is on the other side of the equal sign!
Answer:
2
Step-by-step explanation:
4x^3 + 2 = 34
4x^3 = 32
x^3 = 8
x=2
