Answer:
Question 1:
(A) 22.5 weeks
Question 2:
(A) 35
Step-by-step explanation:
Question 1:
Given:
The line of best fit is given as:
Where,
Height of the puppy (y) = 54 cm
Now, plug in the value of 'y' and solve for 'x'. This gives,
Therefore, the puppy was 22.5 weeks old when he was 54 cm tall.
Question 2:
The line of best fit is given as:
Where,
Number of times at bat (x) = 175
Now, plug in the value of 'x' and solve for 'y'. This gives,
Therefore, the number of hits is 35 to the nearest whole number.
The numbers given in the previous answer cannot right be because the mode would be 130 and 110, and the problem specifiies that the mode is 110.
This is how you can obtaind the numbers, step by step:
1) If the median is 130, there are 3 numbers less than 130 and 3 number over 130.
2) One of the numbers below 130 is 100 (the minimum reported), then the other two has to be 110 because 110 is the mode.
Now we have these numbers for sure 100, 110, 110 and 130 and 300.
3) We need to find only two more numbers, which are greater than 130 y less than 300.
4) Given the the mean is 150, the sum of all the numbers is 150*7 = 1050.
and the two so far unknown numbers add up : 1050 - 300 - 130 - 110 - 110 - 100 = 300.
5) The two numbers have to be different and greater than 130, then they are 140 and 160.
They cannot be 150 because they would be equal, they cannot be 170 and 130, because 130 is not the mode.
So you can be sure that the other two numbers are 140 and 160 and now we have the list of the seven numbers complete:
Answer: 100, 110, 110, 130, 140, 160 and 300
The answer would be 85% because 17/20= .85 and if you multiply that by 100 it’s 85
Hope you could understand.
If you have any query, feel free to ask.
The equation of a straight line is given by:
y = mx + c
where m is the slope and c is the y-intercept.
From the given graph, the y-intercept is 1.
The slope of a straight line is given by:
Where
and
are two points on the line.
From the graph, (0, 1) and (14, 8) are two points on the line, thus:
Therefore, the equation representing the graph is
