Answer:
1.71 × 10²¹ molecules
Explanation:
1 gram is equal to 1000 milligrams. The mass in grams corresponding to 500 mg is:
500 mg × (1 g / 1000 mg) = 0.500 g
The molar mass of ascorbic acid is 176.12 g/mol. The moles corresponding to 0.500 grams of ascorbic acid are:
0.500 g × (1 mol/ 176.12 g) = 0.00284 mol
In 1 mole of ascorbic acid, there are 6.02 × 10²³ molecules of ascorbic acid (Avogadro's number). The molecules in 0.00284 moles are:
0.00284 mol × (6.02 × 10²³ molecules/ 1 mol) = 1.71 × 10²¹ molecule
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PH is simply a convenient way to denote hydronium ion concentration (usually in moles per liter or molarity). pH is calculated from the given concentration using the equation: pH = -log [H3O⁺]
To find [H3O+] from the given equation, we apply the antilog.
[H3O⁺] = 10⁻⁽pH⁾ or ten raised to the negative value of pH
A solution with a pH of 3.43 has a hydrogen ion concentration of 3.7154x10^-4 moles per liter.
Answer:
Empirical formula: CH₂
Explanation:
We need to find the empirical formula of a compound that has carbon and hydrogen.
To find the empirical formula of any compound, if we have the mass or mass percent, we should follow 3 steps:
<u>1. Calculate the moles, dividing by the atomic weight.</u>
The atomic weight for carbon and hydrogen are 12 g/mol and 1 g/mol, so, doing the division we have:
C = 85.5 / 12 = 7.125
H = 14.3 / 1 = 14.3
<u>2. Determine the number of atoms of each element in the formula</u>
To do this, we just divide the previous moles by the lowest quantity we obtain. In this case, the carbon:
C = 7,125 / 7,125 = 1
H = 14,3 / 7,125 = 2
This means we have 1 atom of carbon and 2 atoms of hydrogen.
<u>3. Write the empirical formula with the previously obtained atoms</u>
Now that we obtained the atoms of each element, we just write the empirical formula with these numbers:
C₁H₂ but we can neglect the number one so:
<h2>
Empirical formula: CH₂</h2>
Hope this helps
The reaction equation is:
Li + Br → LiBr
39 grams of Li = 39 / 7 = 5.57 moles of lithium
41.5 grams of Br = 41.5 / 80 = 0.52 mole of bromine