In these solutions, identify the solute and the

Hydrogen bonds can be found between molecules of which substance?

Ratling [72]

I believe the answer is D

5 0

3 years ago

A student accidentally drops the watch glass atop the evaporating dish containing the

user100 [1]

Answer:

the experiment measurements might been thrown off

Explanation:

6 0

3 years ago

How many moles of water will be generated during the combustion of 0.38 moles of methyl alcohol (CH3OH)? 2CH3OH + 3O2 2CO2 + 4H2

ELEN [110]

You already got the balanced equation. So the ratio of mole number is the ratio of the coefficient. Then the ratio of methyl alcohol and water is 2:4=1:2. The water generated is 0.38*2=0.76 mol.

6 0

3 years ago

How do you balance these two chemical equations?

Vlada [557]

In order to balance both of the reactions you need to make sure that both sides of the reaction have the same number of atoms for each atom in order to follow conservation of mass.

KCl+F₂→KF+Cl₂
Notice how in the above reaction there are two chlorine atoms on the products side (right side) and only one atom of chlorine on the reactants side (left side). you want both the reactants and products side to have the same amount chlorine and to do this multiply KCl by 2. Fluorine however, has 2 atoms on the reactant side and 1 atom on the product side. to fix this multiply KF by 2. Therefore the balanced reaction is: 2KCl+F₂→2KF+Cl₂
notice how both sides of the reaction have equal numbers of each atom.

Mg+HCl→MgCl₂+H₂
the above reaction has 2 atoms of H on the products side and only 1 atom of H on the reactants side. That means you have to multiply HCl by 2. Now you have the equation Mg+2HCl→MgCl₂+H₂. As you can see now we have equal numbers of all the atoms on both sides which means that that is the balanced equation.

I hope this helps. Let me know if you have any further questions or need anything to be clarified.

6 0

4 years ago

You have 750 grams of water at 80° Celsius. Which of the following would lower the temperature of the water by 10° Celsius? (1 p

dem82 [27]

Answer:

adding 750 grams of water at 60° Celsius .

Explanation:

We can calculate the amount of heat lost from 750 grams of water at 80°C to be lowered by 10°C using the relation:

Q = m.c.ΔT,

Where, Q is the amount of heat lost by water (Q = ??? J).

m is the mass of water (m = 750.0 g).

c is the specific heat capacity of the water (c = 4.18 J/g.°C).

ΔT is the temperature difference (ΔT = final T - initial T = - 10.0°C, the temperature of water is lowered by 10.0°C).

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(- 10.0°C) = - 31350.0 J = -31.350 kJ.

Now, we can calculate the Q that is gained by the different added amounts of water:

adding 750 grams of water at 50° Celsius :

ΔT = 70.0°C - 50.0°C = 20.0°C,

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(20.0°C) = 62700.0 J = 62.70 kJ.

adding 325 grams of water at 60° Celsius :

ΔT = 70.0°C - 60.0°C = 10.0°C,

∴ Q = m.c.ΔT = (325.0 g)(4.18 J/g.°C)(10.0°C) = 13585.0 J = 13.585 kJ.

adding 750 grams of water at 60° Celsius :

ΔT = 70.0°C - 60.0°C = 10.0°C,

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(10.0°C) = 31350.0 J = 31.350 kJ.

adding 1000 grams of water at 55° Celsius:

ΔT = 70.0°C - 55.0°C = 15.0°C,

∴ Q = m.c.ΔT = (1000.0 g)(4.18 J/g.°C)(15.0°C) = 62700.0 J = 62.70 kJ.

So, the right choice is:

adding 750 grams of water at 60° Celsius

8 0

4 years ago