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2 years ago

An atom of an element contains 9 protons. Which element is it?

Chemistry

1 answer:

lina2011 [118]2 years ago

3 0

Fluorine

Explanation:

By looking at the periodic table, you will see that Fluorine has 9 protons. Since the number of electrons equal the number of protons, Fluorine has 9 electrons as well. Meanwhile, it's mass number of 19, minus 10 neutrons, gives you 9 protons or electrons. Hence, the atom would be Fluorine.

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A solution of KCIO3 is prepared using 75 grams of the solute in enough water to make 0.250 liters of solution. The gram-formula

charle [14.2K]

Using the mass/volume percentage method for percentages of the solution, you simply divide the grams of solute by the volume of the solution and multiply by 100 to get your percentage.
(75.0g/250mL)•100 = 30.0% solute

3 0

3 years ago

Need help fast please 15 points!!!

In-s [12.5K]

Answer:

C. disposition and condensation

Explanation:

8 0

2 years ago

In compounds,has an oxidation number 1-

alex41 [277]

Fluorine in compounds is always assigned an oxidation number of -1

5 0

3 years ago

What are deltaTb and deltaTf for an aqueous solution that is 1.5g nacl in 0.250kg h2o? Given Kb=0.51 C/m and kr=1.86 C/m

bulgar [2K]

Answer:

$T_f$ for given question is 2.79 and $T_b$ is 0.52

$\Delta T_b = I \times K_b \times m$ {i- vant hoff’s constant ; Kb- constant ; m molarity }

M = no. of moles of the solute present in one kg of solution

Let the weight of amount of solute be “w” and its molecular mass be “M”

Let the mass of the solvent in the given question be “x”

$\Delta T_b = I \times K_b \times (w/M)/ x$

$\Delta T_b = I \times K_b \times w/Mx$

$\Delta T_b = 1 \times 0.51 \times1.5/(0.250 \times 58.44) = 0.052$

$\Delta T_f = M \times K_f = 1.86 \times 1.5 = 2.79$

4 0

2 years ago

When a saturated solution of NH4Br dissolved in 100 grams of water is cooled from 60°C to 30°C, how much NH4Br will precipitate?

stepladder [879]

Answer:

$m_{precipitated}=24.8g$

Explanation:

Hello,

In this case, since at 60 °C, 108 grams of ammonium bromide are completely dissolved in 100 grams of water for a saturated solution, once it is cooled to 30 °C, wherein only 83.2 grams are completely dissolved in 100 grams of water, the following mass will precipitate:

$m_{precipitated}=108g-83.2g\\\\m_{precipitated}=24.8g$

Best regards.

8 0

2 years ago