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alukav5142 [94]
3 years ago
14

What else is produced when sodium carbonate decomposes? Na2CO3 Na2O +

Chemistry
2 answers:
andriy [413]3 years ago
7 0

When a single compound breaks down into two or more compounds or elements in a chemical reaction then it is known as decomposition reaction.

The chemical symbol for sodium carbonate is Na_2CO_3.

The decomposition of sodium carbonate is:

Na_2CO_3\rightarrow Na_2O+ CO_2

The decomposition of sodium bicarbonate, Na_2CO_3 will result in the formation of sodium oxide, Na_2O and carbon dioxide, CO_2.

Hence, carbon dioxide, CO_2 will produce with sodium oxide, Na_2O on decomposition of Na_2CO_3.

White raven [17]3 years ago
4 0

Na2CO3 Na2O +CO2   CO2 is the answer

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2. Suppose that 21.37 mL of NaOH is needed to titrate 10.00 mL of 0.1450 M H2SO4 solution.
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Answer:

0.1357 M

Explanation:

(a) The balanced reaction is shown below as:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

(b) Moles of H_2SO_4 can be calculated as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

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For H_2SO_4 :

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Volume = 10.00 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10×10⁻³ L

Thus, moles of H_2SO_4 :

Moles=0.1450 \times {10\times 10^{-3}}\ moles

Moles of H_2SO_4  = 0.00145 moles

From the reaction,

1 mole of H_2SO_4 react with 2 moles of NaOH

0.00145 mole of H_2SO_4 react with 2*0.00145 mole of NaOH

Moles of NaOH = 0.0029 moles

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Molarity = Moles / Volume = 0.0029 /  21.37×10⁻³  M = 0.1357 M

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3 years ago
The ratio of chlorine to hydrogen chloride in the reaction<br><br> H2(g) + Cl2 (g) -&gt; 2 HCl(g) is
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