Answer:
Y = 92.5 %
Explanation:
Hello there!
In this case, since the reaction between lead (II) nitrate and potassium bromide is:

Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:

Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:

And the resulting percent yield:

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Answer:
C. H2O diffuses in.
Explanation:
<em>The phospholipids-made synthetic vesicle in this case will act like a semi-permeable membrane while the solution in the interior lumen will be hypertonic to the surrounding pure water. </em>
<em>Hence, water molecules will diffuse into the lumen through the semi-permeable membrane because of the osmotic gradient that exist between the internal and the surrounding solution of the vesicle.</em>
Answer:
Rotate the types of drops grown
Explanation:
Answer:
I'd say it's a mixture, because you are putting different ingredients together to make something new; aka this salad.
The mass in grams of the given beryllium sulfide is 99.2 g. The correct option is the second option - 99.2 g BeS
<h3>Calculating mass of a compound </h3>
From the question, we are to determine the mass of the given beryllium sulfide.
From the given information,
Number of moles of beryllium sulfide (BeS) given = 2.42 moles
Using the formula,
Mass = Number of moles × Molar mass
Molar mass of BeS = 41 g/mol
Then,
Mass of BeS = 2.42 × 41
Mass of BeS = 99.22
Mass of BeS ≅ 99.2 g
Hence, the mass in grams of the given beryllium sulfide is 99.2 g. The correct option is the second option - 99.2 g BeS
Learn more on Calculating mass of a compound here: brainly.com/question/18142599