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alukav5142 [94]
3 years ago
14

What else is produced when sodium carbonate decomposes? Na2CO3 Na2O +

Chemistry
2 answers:
andriy [413]3 years ago
7 0

When a single compound breaks down into two or more compounds or elements in a chemical reaction then it is known as decomposition reaction.

The chemical symbol for sodium carbonate is Na_2CO_3.

The decomposition of sodium carbonate is:

Na_2CO_3\rightarrow Na_2O+ CO_2

The decomposition of sodium bicarbonate, Na_2CO_3 will result in the formation of sodium oxide, Na_2O and carbon dioxide, CO_2.

Hence, carbon dioxide, CO_2 will produce with sodium oxide, Na_2O on decomposition of Na_2CO_3.

White raven [17]3 years ago
4 0

Na2CO3 Na2O +CO2   CO2 is the answer

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How many moles of glucose can be produced
Arturiano [62]

Answer:

moles of glucose

<u>2.3166 moles of glucose</u>

<u></u>

Explanation:

The balance reaction for the formation of glucose is :

6CO_{2}+6H_{2}O\rightarrow C_{6}H_{12}O_{6}+6O_{2}

here , CO2 = carbon dioxide

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C6H12O6 = glucose

O2 = Oxygen

According to this equation :

6 mole of CO2 = 6 mole of H2O = 1 mole of C6H12O6 = 6 mole of O2

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So,

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1 mole of CO2 will produce =

\frac{1}{6} moles of glucose

13.9 moles of CO2 will produce :

\frac{1}{6}\times 13.9

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5 0
4 years ago
The density of a 45.0 mass % solution of ethanol (C2H5OH) in water is 0.873 g/mL. What is the molarity of the solution?
antoniya [11.8K]

Answer : The concentration of solution is, 8.53 M.

Explanation :

As we are given, 45.0 mass % solution of ethanol in water that means 45.0 g of ethanol present in 100 g of solution.

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}

\text{Volume of solution}=\frac{100g}{0.873g/mL}=114.5mL

Now we have to calculate the molarity of solution.

Mass of C_2H_5OH = 45.0 g

Volume of solution = 114.5 mL

Molar mass of C_2H_5OH = 46.07 g/mole

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Formula used :

\text{Molarity}=\frac{\text{Mass of }C_2H_5OH\times 1000}{\text{Molar mass of }C_2H_5OH\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{45.0g\times 1000}{46.07g/mole\times 114.5mL}=8.53mole/L=8.53M

Therefore, the concentration of solution is, 8.53 M.

6 0
3 years ago
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