<span>Scientists believe that tectonic activity is not occurring on the moon. This is <span>because the moon lacks radioactive decay. The moon is not constantly supplied heat and energy from decaying unstable isotopes like Earth. Also, Earth is heated by the original heat during its formation. Since the moon was most likely broken off from earth, it lacks this central heat. @Kb0812 Hope this helps and if your feeling generous feel free to leave a rate, thanks and brainliest because it would really help me reach expert and I would appreciate it ;)</span></span>
For 1 through 4, you can look that up on google because their definitions are pretty decent.
5. is speeding up (acceleration)
6.slowing down or turning
7.speeding up
those are the only ones i somewhat know
Biome, though some might say ecosystem instead. Biomes are very large ecosystems that cover broad areas.<span>If they specify "one" reef, then they are probably looking for "ecosystem"</span>
Answer: Operant speech training
Explanation:
Autism Spectrum Disorder is developmental dysfunction that leads to notable social, communication, and behavioral challenges.
Operant speech training is a plan employed to make children makes use of language appropriately, it is mostly used for aiding speech in Autism Spectrum Disorder (ASD).
This approach involved the step by step procedures of increasing child’s vocalization, imitation of sounds and words, teaching the child the meanings of words, and teaching the child. how to use language to label objects. And how to express languages to make verbal requests and desires
Answer:
The correct answer is E. none of the above. The population will drops below 100 when t ≥ 38.
Explanation:
Given A= A0 e^kt. The population 10 years ago is A0, the population today is A(10), and we have to find the value of "k" and then the time when population drops below 100.
So, A(t) = 1700 e^kt ⇒ A(10) = 1700 e^k(10) ⇒ 800 = 1700 e^k(10) ⇒
800/1700 = e^k(10) ⇒ln (800/1700) = k(10) ln e ⇒ -0.754/10 = k ⇒
k = -0.0754.
Now you have all the parameters, so you can find the time at which the population drops below 100.
A(t) = 1700 e^kt ⇒ 100 = 1700 e^(-0.0754)t ⇒100/1700 = e^(-0.0754)t ⇒
ln(100/1700) = (-0.0754)t ln e ⇒ [ln(100/1700)]/(-0.0754) = t ⇒
t = 38.
So, the population will drops below 100 when t ≥ 38.
