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3 years ago

NEED HELP PLEASE

Mathematics

2 answers:

dusya [7]3 years ago

5 0

Answer: It is over the goal post by 60 feet .

postnew [5]3 years ago

3 0

Answer:

It goes over the goal post by 6 feet

Step-by-step explanation:

The football will be at the same x position as the goal when x = 40. When x = 40, y = -0.03 * 40² + 1.6 * 40 = 16. The height of the goal post can be represented by the equation y = 10. Since 16 > 10, the football goes over the goal post by 16 - 10 = 6 feet.

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Warmup Day 1

olga nikolaevna [1]

Answer:

274

Step-by-step explanation:

(52 + 4) * 5 - 2 + (-4)

56 * 5 - 2 + (-4)

56 * 5 - 2 - 4

280 - 2 - 4

278 - 4

274

6 0

3 years ago

Read 2 more answers

Simplify the expression:<br> (5h + 7) – 2h<br><br><br> Will mark brainlist

Citrus2011 [14]

3h + 7 next time do it you self smh

3 0

3 years ago

suppose you have ab on a coordinate plane located at a(-3,-4) and b(5,-4). under a dilation centered at (9,0), ab becomes a'b' w

Galina-37 [17]

The distace between the center of dilation and point a is diven by:

$d=\sqrt{(9-(-3))^2+(0-(-4))^2} \\ \\ =\sqrt{(9+3)^2+(0+4)^2}=\sqrt{12^2+4^2} \\ \\ =\sqrt{144+16}=\sqrt{160}=\sqrt{16\times10}=4\sqrt{10}$

The distance between the center of dilation and point a' is given by:

$d=\sqrt{(9-6)^2+(0-(-1))^2} \\ \\ =\sqrt{3^2+(0+1)^2}=\sqrt{3^2+1^2} \\ \\ =\sqrt{9+1}=\sqrt{10}$

It can be seen that the distance from the center of dilation to the image is 1/4 times the distance from the centre of dilation to the preimage.

Therefore, the scale factor is 1/4.

7 0

3 years ago

The illustration below shows the graphs of fourteen functions.

Travka [436]

Due to <em>length</em> restrictions, we kindly invite to check the explanation of this question to understand the derivation of the <em>polynomic</em> expressions.

<h3>How to determine a family of cubic functions</h3>

<em>Cubic</em> functions are polynomials of grade 3. In this case, we have pairs of <em>cubic</em> functions of the following form:

y = (x - h)³ + k (1)

y = - (x - h)³ + k (2)

a) Where (h, k) are the coordinates of the vertex of each <em>cubic</em> function. There is a translation of (x, y) = (3, 1) between each two <em>consecutive</em> pairs of <em>cubic</em> functions. Hence, we have the following fourteen cubic functions:

y = (x + 9)³ - 3
y = - (x + 9)³ - 3
y = (x + 6)³ - 2
y = - (x + 6)³ - 2
y = (x + 3)³ - 1
y = - (x + 3)³ - 1
y = x³
y = - x³
y = (x - 3)³ + 1
y = - (x - 3)³ + 1
y = (x - 6)³ + 2
y = - (x - 6)³ + 2
y = (x - 9)³ + 3
y = - (x - 9)³ + 3

b) Another family of functions with a similar pattern is shown below:

y = (x + 9)² - 3
y = - (x + 9)² - 3
y = (x + 6)² - 2
y = - (x + 6)² - 2
y = (x + 3)² - 1
y = - (x + 3)² - 1
y = x²
y = - x²
y = (x - 3)² + 1
y = - (x - 3)² + 1
y = (x - 6)² + 2
y = - (x - 6)² + 2
y = (x - 9)² + 3
y = - (x - 9)² + 3

To learn more on cubic functions: brainly.com/question/25732149

#SPJ1

8 0

2 years ago

1/3 of 2 feet=(?)inches<br><br>1/6 of 3 yards=(?)inches<br><br>

melomori [17]

Problem 1

1 ft = 12 inches

2 ft = 24 inches (multiply both sides by 2)

Multiply by 1/3 to get (1/3)*24 = 24/3 = 8

<h3>Answer: 8 inches</h3>

========================================

Problem 2

1 yard = 3 feet

3 yards = 9 feet (multiply both sides by 3)

1 ft = 12 inches

9 ft = 108 inches (multiply both sides by 9)

so overall, 3 yards = 108 inches

Multiply this by 1/6

(1/6)*(108 inches) = 108/6 = 18 inches

<h3>Answer: 18 inches</h3>

note: 18 inches = 12 inches + 6 inches = 1 ft, 6 inches = 1.5 ft

5 0

3 years ago