Answer:
1.5
Step-by-step explanation:
4x + 17 = 23
- 17 -17
4x=6
then divide 4 from both sides and you get
x=1.5
The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.
Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s
The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.
Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s
When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.
Answer: 7 s
Answer:
The mean will be the best instrument to measure Royston's performance
Step-by-step explanation:
hope this helps
All you have to do is plug in the number for x, and find y. I will write this out as if in that chart you have shown.
x y = 9 - 3x y
_______________________________________
0 y = 9 - 3(0) 9
1 y = 9 - 3(1) 6
2 y = 9 - 3(2) 3
3 y = 9 - 3(3) 0
Hope that helps!!
Step-by-step explanation:
2 : 3 = 6 : x ,
Ratio can be written as
2*3 = 6, we multiply top and bottom of fraction by 3
So value of x=9
4 : 7 = x : 42 ,
7*6 = 42, we multiply top and bottom of fraction by 6
So value of x=24
2x : 48 = 3 : 12,
\frac{3}{12}[/tex] =
2x= 12, so x= 6
12 : 15 = x : 20
,
we multiply top and bottom by 4/3

So value of x=16