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Anni [7]
3 years ago
12

What is the midpoint of the line segment with endpoints (2, 14) and (6, 19)

Mathematics
1 answer:
dedylja [7]3 years ago
4 0

Answer:

(4, 15)

Step-by-step explanation:

let (x,y) is the mid point of line segment with endpoints (2,14) and (6,19)

we have,

x = (2+6)/2 = 4

y = (14+16)/2 = 15

Hence the midpoint of the line segment with endpoints (2,14), (6,19) is (4,15)

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Data:

Formula: diameter = 2*radius

Formula: (<span>Circle length)
</span>C = 2* \pi *r
<span>
Solving: </span><span>Using the data
</span>diameter = 2*radius
20 = 2*r
2r = 20
r =  \frac{20}{2}
\boxed{r = 10\:ft}

<span>Now, replace in the circumference length formula
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3 years ago
In the figure below, segment CD is parallel to segment EF and point H bisects segment DE :
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Answer:

See explanation

Step-by-step explanation:

In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.

Consider triangles DIH and EGH. In these triangles,

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\triangle DIH\cong \triangle EGH by AAS postulate

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What is the next term ofthe sequence 5z, 8x, 11v,...?
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