<u>Answer:</u>
B
<u>Explanation:</u>
<u>Solve for n:</u>
Subtract 8 on both sides.
5n + 8 = 30
-8 -8
Divide by 5 on both sides.
5n = 22
--- ----
5 5
Getting a solution of 4 2/5.
n = 4 2/5
<u>Check:</u>
5(4 2/5) + 8 = 30
22 + 8 = 30
30 = 30
Answer:
hi how are you are you good just asking do not hace the answer
Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so
.
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when
.
So




A task time of 177.125s qualify individuals for such training.
Answer:
Step-by-step explanation:
c