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sergeinik [125]

3 years ago

5

How to find the volume of a triangular prisim

2 answers:

aleksandrvk [35]3 years ago

7 0

Answer:

V=1

4h﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4

Step-by-step explanation:

Leni [432]3 years ago

6 0

By multiplying the base times the height

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which equations are equivalent to 3/4+m=-7/4 check all that apply m=10/4 m=-10/4 m=-5/2 11/4+m=-1/4 -5/4+m=-15/4 m+2=-0.5 Help f

Alecsey [184]

Answer:

The correct choices are; B,C,E, and F.

Step-by-step explanation:

The given equation is;

$\frac{3}{4}+m=-\frac{7}{4}$

We solve for m to obtain:

$m=-\frac{7}{4}-\frac{3}{4}=-2.5$

We also solve the remaining equations to see which ones give the same result.

A: $m=\frac{10}{4} =2.5$

B: $m=-\frac{10}{4} =-2.5$

C: $m=-\frac{5}{2} =-2.5$

D: $\frac{11}{4}+m=-\frac{1}{4}$

$m=-\frac{1}{4}-\frac{11}{4}=-3$

E: $-\frac{5}{4}+m=-\frac{15}{4}$

$m=-\frac{15}{4}+\frac{5}{4}=-2.5$

F: $m+2=-0.5$

$m=-0.5-2=-2.5$

The equivalent equations are; B,C,E, and F.

3 0

3 years ago

Read 2 more answers

What is [(7x^3)(y^2)]^2/7 in radical form?

GuDViN [60]

Remember
$x^ \frac{m}{n} = \sqrt[n]{x^m}$
and
$(zy)^m=(z^m)(y^m)$
and
(x^m)^n=x^(mn)

so
$((7x^3)(y^2))^ \frac{2}{7} = \sqrt[7]{((7x^3)(y^2))^2}$ =
$\sqrt[7]{((7x^3)^2(y^2)^2)}$ =
$\sqrt[7]{((7^2x^6)(y^4))}$ =
$\sqrt[7]{((49x^6)(y^4))}$ =
$\sqrt[7]{49x^6y^4}$

8 0

3 years ago

PLEASE HELP MATH

Novosadov [1.4K]

I believe C is your answer.
I hope this helps!

7 0

2 years ago

Read 2 more answers

Geometry help it’s easy!!!

Ede4ka [16]

Answer:

c

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which of the following best completes the proof showing that ΔWXZ ~ ΔXYZ?

skelet666 [1.2K]

Angles formed by the segment $\overline{XZ}$ in the triangles ΔWXZ, and ΔXYZ, are equal and the given corresponding sides are proportional.

The option that best completes the proof showing that ΔWXZ ~ ΔXYZ is; <u>16 over 12 equals 12 over 9</u>

Reasons:

The proof showing that ΔWXZ ~ ΔXYZ is presented as follows;

Segment $\overline{XZ}$ is perpendicular to segment $\overline{WY}$

∠WZX and ∠XZY are right angles by definition of $\overline{XZ}$ perpendicular to $\overline{WY}$

∠WZX in ΔWXZ = ∠XZY in ΔXYZ = 90° (definition)

$\displaystyle \frac{WZ}{XZ} = \frac{16}{12} = \mathbf{ \frac{4}{3}}$

$\displaystyle \mathbf{ \frac{XZ}{ZY}} = \frac{12}{9} = \frac{4}{3}$

Therefore;

$\displaystyle \frac{16}{12} = \frac{12}{9}$ , which gives, $\displaystyle \mathbf{\frac{WZ}{XZ} }= \frac{XZ}{ZY}$

Given that two sides of ΔWXZ are proportional to two sides of ΔXYZ, and

that the included angles between the two sides, ∠WZX and ∠XZY are

congruent, the two triangles, ΔWXZ and ΔXYZ are similar by Side-Angle-

Side, SAS, similarity postulate.

The option that best completes the proof is therefore;

$\displaystyle \frac{16}{12} = \frac{12}{9}$ which is; <u>16 over 12 equals 12 over 9</u>

Learn more about the SAS similarity postulate here:

brainly.com/question/11923416

4 0

2 years ago