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geniusboy [140]
3 years ago
10

What is the interval notation for y<5?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Hey there!☺

Answer: (-∞, 5)

Explanation:

You need to convert the inequality as an interval notation.

y as interval notation would be written like this:

(-∞, 5)

Hope this helps!

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Two nonadjacent angles formed by two intersecting lines are
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Two vertical angles are formed. These angles are also equal to each other.
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Drag each tile to the correct box. not all tiles will be used.Chris plans to mulch the border surrounding a rectangular garden i
amm1812

Length (L): 2w + 3

width (w): w

border (b): \frac{1}{4} w

Area (A) = (L + b) * (w + b)   <em>NOTE: This is assuming the width also has a border</em>

              = (2w + 3 + \frac{1}{4} w) * (w + \frac{1}{4} w)

              = (2\frac{1}{4} w + 3)(1\frac{1}{4} w)

              = (\frac{9}{4} w + 3)(\frac{5}{4} w)

              = \frac{45}{16} w^2 + \frac{15}{4}w


5 0
3 years ago
How can I find the least common multiple of two or more numbers ?
Anettt [7]

Example: 30 and 42

Factor them.

2 x 3 x 5 = 30

2 x 3 x 7 = 42

Select the highest amount of each factor.

2 x 3 x 5 x 7 = 210, the LCM

8 0
3 years ago
Find sin 2x, cos 2x, and tan 2x from the given information.<br> cscx=4,tanx&lt;0.
lutik1710 [3]

Answer:

Step-by-step explanation:

Given the expression cosec (x) = 4 and tan(x)< 0

since cosec x = 1/sinx

1/sinx = 4

sinx = 1/4

From SOH, CAH TOA

sinθ = opposite/hypotenuse

from sinx = 1/4

opposite = 1 and hypotenuse = 4

to get the adjacent, we will use the Pythagoras theorem

adj² = 4²-1²

adj² = 16-1

adj ²= 15

adj = √15

cosx = adj/hyp = √15/4

tanx = opposite/adjacent = 1/√15

since tan < 0, then tanx = -1/√15

From double angle formula;

sin2x = 2sinxcosx

sin2x = 2(1/4)(√15/4)

sin2x = 2√15/16

sin2x = √15/8

for cos2x;

cos2x = 1-2sin²x

cos2x = 1-2(1/4)²

cos2x = 1-2(1/16)

cos2x= 1-1/8

cos2x = 7/8

for tan2x;

tan2x  = tanx + tanx/1-tan²x

tan2x = 2tanx/1-tan²x

tan2x = 2(-1/√15)/1-(-1/√15)²

tan2x = (-2/√15)/(1-1/15)

tan2x = (-2/√15)/(14/15)

tan2x = -2/√15 * 15/14

tan2x = -30/14√15

tan2x = -30/7√15

rationalize

tan2x =  -30/7√15 * √15/√15

tan2x =  -30√15/7*15

tan2x =  -2√15/7

5 0
3 years ago
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