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geniusboy [140]
3 years ago
10

What is the interval notation for y<5?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Hey there!☺

Answer: (-∞, 5)

Explanation:

You need to convert the inequality as an interval notation.

y as interval notation would be written like this:

(-∞, 5)

Hope this helps!

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Matt started doing extra chores around the house and his allowance changed from $30 per week to $40 per week. What is the percen
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Answer:

33.3%

Step-by-step explanation:

Let's say the percent change is x%. Then the equation is:

30 + x% * 30 = 40

Subtract 30 from both sides:

x% * 30 = 10

Divide by 30:

x% = 10/30 = 1/3

Remember that % simply means "out of 100", so:

x/100 = 1/3

Multiply both sides by 100:

x = (1/3) * 100 = 33.3%

3 0
3 years ago
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One year the price of wheat was $8.87 the next year the price was $9.60 route is the price per bushel of wheat for each year to
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  • <em>I think you mean this right Both are $10.00</em>
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What is the solution to x-4y=-5 and -x+6y=7
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<span>  x - 4y = -5
-x + 6y = 7
---------------add
       2y = 2
         y = 1

</span>     x - 4y = -5 
  x - 4(1) = -5 
      x - 4 = -5
           x = -1

answer
x = -1 and y = 1
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Simplify the expression
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Step-by-step explanation:

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4 0
3 years ago
Six hundred paving stones were examined for cracks, and 20 were found to be cracked. The same 600 stones were then examined for
spin [16.1K]

Answer:

a) probability that is cracked=1/30 (3.33%)

b) probability that is discoloured = 29/600 (4.83%)

c) probability that is cracked and discoloured =  11/600 (1.83%)

Step-by-step explanation:

assuming that each stone is equally likely to be chosen then defining the events C= the stone is cracked , D= the stone is discoloured , N= the stone is neither cracked or discoloured, then

P(C)= number of favourable outcomes/total number of outcomes = 20 stones/600 stones = 1/30 (3.33%)

P(D)= number of favourable outcomes/total number of outcomes = 29 stones/600 stones = 29/600 (4.83%)

the probability that is discoloured and cracked is P(C∩D) , where

P(C∪D)=P(C) + P(D)-P(C∩D)

and

P(C∪D)= 1- P(N)

thus

1- P(N)=P(C) + P(D)-P(C∩D)

P(C∩D)= P(N)+P(C)+P(D) -1

replacing values

P(C∩D)= P(N)+P(C)+P(D)=562/600 + 20/600 + 29/600 -1= 611/600 -1 = 11/600

thus

P(C∩D)=  11/600 (1.83%)

3 0
3 years ago
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