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PSYCHO15rus [73]
3 years ago
10

Find the value of z and the length of side RS.

Mathematics
1 answer:
Stells [14]3 years ago
6 0

<em>answer \\ z \: is \: equal \: to \: 12 \: units \\ side \: rs \: measures \: 9 \: units \: long \\ \: please \: see \: the \: attached \: picture \: for \: full \: solution \\ hope \: it \: helps</em>

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Anastasia gets overtime (time and a half) for every hour she works over 40 hours. If her hourly pay is $28.50, how much would sh
tamaranim1 [39]

Answer:

142.50

Step-by-step explanation:

28.50=1 hour so you would do 28.50 times the amount of hours she works. She worked 51 hours so you would do 28.50x50. You answer is 142.50

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3 years ago
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The answer is 16 yellow flowers
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A geologist noticed that a land along a fault line moved 24.8 centimeters over the past 175 years . On average, how much did the
olasank [31]

Answer:

On average, the land moved 0,14 cm each year.

Step-by-step explanation:

To know how much did, on average, the land move,  we should divide the total number of cm over the total number of years:

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x=0,1417 cm each year

If we divide years over cm we will get x in years each cm, which is wrong.

Because the problem asks for the answer rounded to the hundredths place:

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8 0
3 years ago
What's the answer for 4d - 35= -3
Ket [755]

Answer:

The answer is <u>8</u>.

Step-by-step explanation:

Given:

4d - 35= -3.

Now, the solution:

4d-35=-3

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4d=-3+35

4d=32

Dividing both sides by 4 we get:

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3 0
3 years ago
The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.
ehidna [41]
1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
     i) bisect the angles so m(ODC)=60°/2=30°

     ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, DO= \sqrt{ DC^{2}- OC^{2} }=  \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}= 
=\sqrt{9}* \sqrt{3} =3\sqrt{3}  (in)

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}==2*9 \sqrt{3}=18 \sqrt{3} (in^{2})

6 0
3 years ago
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