Answer:
Explanation:
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In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:
Then, the liters of solution:
Finally, the molarity turns out:
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Answer:
Dissociation Equations Worksheet
Write balanced chemical equations to represent the slight dissociation or the
complete dissociation for 1 mole of the following compounds. In the case of slight
dissociation use a double arrow and for complete dissociation use a single arrow.
Include phase notation in the equations.
1) silver chloride
2) sodium acetate
3) ammonium sulfate
4) calcium carbonate
5) potassium carbonate
6) sodium hydroxide
7) silver chlorate
8) iron(II) sulfate
9) lead(II) phosphate
10) lead(II) chromate
11) iron(III) chloride
12) calcium nitrate
13) iron(III) oxide
14) copper(II) sulfate
15) mercury(II) sulfide
16) zinc chloride
17) lead(II) acetate
18) aluminum phosphate
Solutions
1) AgCl(s) ↔ Ag+
(aq) + Cl-
(aq)
2) NaC2H3O2(s) Æ Na+
(aq) + C2H3O2
-
(aq)
3) (NH4)2SO4(s) Æ 2NH4
+
(aq) + SO4
2-(aq)
4) CaCO3(s) ↔ Ca2+(aq) + CO3
2-(aq)
5) K2CO3(s) Æ 2K+
(aq) + CO3
2-(aq)
6) NaOH(s) Æ Na+
(aq) + OH-
(aq)
7) AgClO3(s) Æ Ag+
(aq) + ClO3
-
(aq)
8) FeSO4(s) Æ Fe2+(aq) + SO4
2-(aq)
9) Pb3(PO4)2(s) ↔ 3Pb2+(aq) + 2PO4
3-(aq)
10) PbCrO4(s) ↔ Pb2+(aq) + CrO4
2-(aq)
11) FeCl3(s) Æ Fe3+(aq) + 3Cl-
(aq)
12) Ca(NO3)2(s) Æ Ca2+(aq) + 2NO3
-
(aq)
13) Fe2O3(s) ↔ 2Fe3+(aq) + 3O2-(aq)
14) CuSO4(s) Æ Cu2+(aq) + SO4
2-(aq)
15) HgS(s) ↔ Hg2+(aq) + S2-(aq)
16) ZnCl2(s) Æ Zn2+(aq) + 2Cl-
(aq)
17) Pb(C2H3O2)2(s) Æ Pb2+(aq) + C2H3O2
-
(aq)
18) AlPO4(s) ↔ Al3+(aq) + PO4
3-(aq)
Explanation:
The environment affects natural selection. Speices need to adapt to changes in environmnet. The weaker organisms which fail to adapt to environment perish while the stronger ones who adapt to the environment survive. This is how environment affects natural selection.
Found it http://my.ccsd.net/userdocs/documents/uGKpi9UAEwFpSIgE.pdf