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alisha [4.7K]
3 years ago
7

Please help me someone ASAP!!!!

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
6 0

Answer:

Explanation:

g

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How many kilojoules (kJ) in 373 joules (J)?
Nonamiya [84]

Answer: There are 0.373 kJ in 373 joules.

Explanation:

According to the standard conversion units 1 kJ is equal to 1000 J. This means that 1 J is equal to 0.001 kJ.

Hence, 373 joules is converted into kilojoules as follows.

1 J = 0.001 kJ\\373 J = 373 J \times \frac{0.001 J}{1 kJ}\\= 0.373 kJ

Thus, we can conclude that there are 0.373 kJ in 373 joules.

4 0
3 years ago
The molar mass of c3h8o2 (four significant figures) is ________.
Luda [366]
So carbon is 12(3), hydrogen is 1.01 (8), and oxygen is 16(2). Add it all together and you get 76.08 amu. That's molecular. The molar would be in grams (76.08 g). Hope that answered the question. 
6 0
3 years ago
The addition of perchloric acid to pure water causes the conductivity to _________.
Olin [163]
Adding perchloric acid to water would cause it's conductivity to increase.
3 0
3 years ago
Read 2 more answers
An electric fence used to contain cattle works by transmitting energy through a conductor creating an electric _______________.
svetoff [14.1K]

Answer:

Current

Explanation:

An electric fence used to contain cattle works by transmitting energy through a conductor creating an electric current.

An electric fence is usually connected to an electric power source . The connection brings about the flow of electric charges(current) which is aided by the presence of a conductor. The conductor ensures smooth flow of electric current to achieve the main purpose of the fence.

4 0
3 years ago
(a) show that the pressure exerted by a fluid P (in pascals) is given by P= hdg, where h is the column of the fluid in metres, d
Murrr4er [49]

Answer:

<em>56.4 m</em>

<em></em>

Explanation:

volume increases by factor of 6, i.e \frac{V2}{V1} = 6

Initial temperature T1 at bottom of lake =  5.24°C = 278.24 K

Final temperature T2 at top of lake = 18.73°C = 291.73 K

NB to change temperature from °C to K we add 273

Final pressure P2 at the top of the lake = 0.973 atm

Initial pressure P1 at bottom of lake = ?

Using the equation of an ideal gas

\frac{P1V1}{T1} = \frac{P2V2}{T2}

P1 = \frac{P2V2T1}{V1T2} = \frac{0.973*6*278.24}{291.73}

P1 = 5.57 atm

5.57 atm = 5.57 x 101325 = 564380.25 Pa

Density Ρ of lake = 1.02 g/cm^{3} = 1020 kg/m^{3}

acceleration due to gravity g = 9.81 m/s^{2}

Pressure at lake bottom = pgd

where d is the depth of the lake

564380.25 = 1020 x 9.81 x  d

d = \frac{564380.25}{10006.2} = <em>56.4 m</em>

3 0
4 years ago
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