Please help me someone ASAP!!!!

a_sh-v [17]

The correct answer is actually

D. requires a lot of energy to become hot.

As the definition of specific heat is "the heat required to raise the temperature of the unit mass of a given substance by a given amount."

3 0

3 years ago

Consider a 0.12 M solution of a weak polyprotic acid (H2A) with the possible values of Ka1 and Ka2 given here. Calculate the con

tatuchka [14]

The [H3O+] in step 1 is 0.0034 M while the [H3O+] in step 2 is 0.00039 M

<h3>What is the contribution of each step?</h3>

Let us set up the ICE table in each case, for K1;

H2A(aq) + H2O(l)--------> H3O^+(aq) + HA^-(aq)

I 0.12 0 0

C -x +x +x

E 0.12 - x x x

Ka1= [H3O^+] [HA^-]/[ H2A]

Ka1= x^2/ 0.12 - x

1.0×10^−4 = x^2/ 0.12 - x

1.0×10^−4(0.12 - x ) = x^2

1.2 * 10^-5 - 1.0×10^−4x = x^2

x^2 + 1.0×10^−4x - 1.2 * 10^-5 = 0

x =0.0034 M

[H3O+] = 0.0034 M

Again; [H3O+] = [HA^-] = 0.0034 M

HA^-(aq) + H20(l) -------> A^-(aq) + H3O^+

I 0.0034 0 0

C -x + x +x

E 0.0034 - x x x

Ka2= [A^-] [H3O^+]/[HA^-]

5.0×10^−5 = x^2/ 0.0034 - x

5.0×10^−5 (0.0034 - x ) = x^2

1.7 * 10^-7 - 5.0×10^−5x = x^2

x^2 + 5.0×10^−5x - 1.7 * 10^-7 = 0

x=0.00039 M

Learn more about the dissociation of a polyprotic acid:brainly.com/question/14481763

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7 0

1 year ago

On a warm summer day Mrs. camp placed some flowers in a zippered sandwich bag and sealed it with enough air to provide protectiv

Naddika [18.5K]

<span>The flowers undergo photosynthesis so it is expected to release O2. When you zip the flower in a plastic bag and placed it in the refrigerator, the plastic bag will shrink in size. The extra air plus the O2 in the back forms gaseous water. This gaseous water will slowly liquefy and when placed in the fridge, it will condense to form water solids.</span>

6 0

3 years ago

What did the geologist likely observe in the environment to draw this conclusion? Check all that apply. The geologist saw large

Lemur [1.5K]

Answer:

geologist saw a few plant species, the geologist saw a few small insects, the geologist saw remaining soil

Explanation:

I just answered it

5 0

3 years ago

Read 2 more answers

How does ionization of a given molecule affect its distribution between the organic and aqueous layer

iVinArrow [24]

Answer:

Ionized molecules will be found in the aqueous layer

Explanation:

The principle of solvent extraction involves the partitioning of a substance between an aqueous layer and an organic layer. The aqueous layer is polar in nature while the organic layer is nonpolar in nature.

All nonpolar substances are found in the organic layer while all polar substances are found in the aqueous layer. Hence, in the aqueous phase, the following species can be found; positive ions, negative ions and neutral polar molecules or ionic substances.

4 0

3 years ago