Answer:
3,4,5,6,..................any number bigger than 3 can be taken as the answer 
 
        
                    
             
        
        
        
Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean  and standard deviation
 and standard deviation  , the z-score of a measure X is given by:
, the z-score of a measure X is given by:
 
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that 
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus
 
 


Heights of 29.5 and below could be a problem.
 
        
             
        
        
        
The area of the resulting figure will be given by:
∫f(x)dx
f(x)=13/2x^3
thus
∫f(x)dx=13/2∫x³dx=13/8[x^4]
integrating over the inerval
13/8(12^4)-13/8(5^4)
=32680+3/8 sq. units
=
        
             
        
        
        
Answer 
t3/b=x
Step by step explanation 
t = bx/3
Take b/3 to the left hand side
= x = 3t/b
Hope it helped !!
Comment below
        
                    
             
        
        
        
Log number 1 find catalog 5 - 4 = 1 . ( f .g ) 1 log = 0