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3 years ago

11

8TH GRADE MATH HELP IMAGE ATTACHED

1 answer:

Amiraneli [1.4K]3 years ago

4 0

Answer:

see below:

Step-by-step explanation:

print perfect: 15p + 120

artie's print shop: 10p + 160

eight posters to be the same

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What is the value of 3ypower zero

postnew [5]

Answer:

3

$3 {y}^{0}$

$= 3 \times 1$

$= 3$

If any numbers or constant power is zero then it will be 1

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1 year ago

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bearhunter [10]

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3 years ago

Find the 50th term of 15, 9, 3, -3,...

MA_775_DIABLO [31]

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2 years ago

D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

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2 years ago

Tash 3 write the Following in expanded form then in word form. 1. 355,645

Karolina [17]

Answer:

u will get a option like this when u put ur question then u can add photos!!

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2 years ago

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