Answer:
.500 is the nearest hundredth.
Given:
∠JEK + ∠DFH = 90°
Find:
relationship, if any, of ∠JEK to angles CFL, HFG, LFE
Solution:
We note that ∠DFG = 90° = ∠DFH + ∠HFG, so ∠JEK ≅∠HFG.
We also note that ∠HFG and ∠CFL are vertical angles, so ∠JEK ≅∠CFL.
And ∠LFE and ∠DFH are vertical angles, so ∠JEK + ∠LFE = 90°.
Evaluating the choices, we find
A) false. The angles are not complementary, they are equal.
B) false. The angles are not equal, they are complementary.
C) false. The angles are not supplementary, they are equal.
D) TRUE. The angles are equal.
The appropriate choice is ...
D) ∠JEK ≅∠CFL
(1.5)*(2)*(10^(-3)*(10^4) = 3*10^(-3+4) = 3*10^1 = 3*10 = 30 (answer)
Answer:
Step-by-step explanation:
We want to simplify:
We rewrite as positive index to get:
This simplifies to
This will finally give us:
We cannot simplify further.
Hence the simplest form is
