The balanced equation for the reaction is;
3CCl₄ + 2SbF₃ ---> 3CCl₂F₂ + 2SbCl₃
stoichiometry of CCl₄ to SbF₃ is 3:2
number of CCl₄ moles - 7.30 g/ 154 g/mol = 0.0474 mol
number of SbF₃ moles - 5.50 g/ 179 g/mol = 0.0307 mol
if CCl₄ is the limiting reactant,
3 mol of CCl₄ reacts with 2 mol of SbF₃
therefore 0.0474 mol reacts with - 2/3 x 0.0474 = 0.0316 mol
but only 0.0307 mol of SbF₃ is present therefore SbF₃ is the limiting reactant and CCl₄ is in excess
stoichiometry of SbF₃ to CCl₂F₂ is 2:3
if 2 mol of SbF₃ forms 3 mol of CCl₂F₂
then 0.0307 mol of SbF₃ forms - 3/2 x 0.0307 = 0.0461 mol
then mass produced - 0.0461 mol x 121 g/mol = 5.58 g
but actual yield was 5.10 g
percent yield = actual yield / theoretical yield x 100 %
= 91.4 % is the percent yield of CCl₂F₂
1) ΔrH = 2mol·ΔfH(NO) - (ΔfH(O₂) + ΔfH(N₂)).
ΔrH = 2 mol · 90.3 kJ/mol - (0 kJ/mol + 0 kJ/mol).
ΔrH = 180.6 kJ.
2) ΔS = 2mol·ΔS(NO) - (ΔS(O₂) + ΔS(N₂)).
ΔS = 2mol · 210.65 J/mol·K - (1mol · 205 J/mol·K + 1 mol · 191.5 J/K·mol).
ΔS = 24.8 J/K.
3) ΔG = ΔH - TΔS.
55°C: ΔG = 180.6 kJ - 328.15 K · 24.8 J/K = 172.46 kJ.
2570°C: ΔG = 180.6 kJ - 2843.15 K · 24.8 J/K = 110.09 kJ.
3610°C: ΔG = 180.6 kJ - 3883.15 K · 24.8 J/K = 84.29 kJ.
Phenotype = Non-red
Genotype = depends on what genes you are using
Explanation :
Isotope : It is defined as the element that have the same number of protons but have the different number of neutrons of each of the atom.
Atomic number is defined as the number of protons or number of electrons.
Atomic number = number of protons = number of electrons
Mass number is defined as the sum of number of protons and number of neutrons.
Number of neutrons = Mass number - Number of protons
For the given options:
(a)
Atomic number = 5
Number of proton = 5
Number of electron = 5
Atomic mass = 10
Number of neutrons = Atomic number - Number of protons
Number of neutrons = 10 - 5 = 5
(b)
Atomic number = 80
Number of proton = 80
Number of electron = 80
Atomic mass = 199
Number of neutrons = Atomic number - Number of protons
Number of neutrons = 199 - 80 = 119
(c)
Atomic number = 29
Number of proton = 29
Number of electron = 29
Atomic mass = 63
Number of neutrons = Atomic number - Number of protons
Number of neutrons = 63 - 29 = 34
(d)
Atomic number = 6
Number of proton = 6
Number of electron = 6
Atomic mass = 13
Number of neutrons = Atomic number - Number of protons
Number of neutrons = 13 - 6 = 7
(e)
Atomic number = 34
Number of proton = 34
Number of electron = 34
Atomic mass = 77
Number of neutrons = Atomic number - Number of protons
Number of neutrons = 77 - 34 = 43
2 C4H8O + 11 O2 —> 8 CO2 + 8 H2O