The electron would absorb a quantum of energy
Answer:
C. The ocean waters are heating up which leads to warmer, less dense air rising to form clouds
Explanation:
Greenhouse gases, due to their ability to trap heat, has caused an increase in the Earth's atmospheric temperature called GLOBAL WARMING. The result is that more heat is being radiated down to Earth from the sun. This could lead to hurricanes in water bodies.
Hurricanes are forceful storms that occurs when ocean waters heat up leading to warmer, less dense air that rises to form clouds. Hurricanes are called tropical cyclones.
Answer:
185.49 grams of Zinc would react with 454g (1lb) of copper sulfate
Explanation:
Yo know the following balanced reaction:
CuSO₄(aq)+ Zn(s) →Cu(s) + ZnSO₄(aq)
You can see that by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents and products are part of the reaction:
- CuSO₄: 1 mole
- Zn: 1 mole
- Cu: 1 mole
- ZnSO₄: 1 mole
Being:
- Cu: 63.54 g/mole
- S: 32 g/mole
- O: 16 g/mole
- Zn: 65.37 g/mole
the molar mass of the compounds participating in the reaction is:
- CuSO₄:63.54 g/mole + 32 g/mole + 4*16 g/mole= 159.54 g/mole ≅ 160 g/mole
- Zn: 65.37 g/mole
- Cu: 63.54 g/mole
- ZnSO₄: 65.37 g/mole + 32 g/mole + 4*16 g/mole= 161.37 g/mole
Then, by stoichiometry of the reaction, the following amounts of mass of reagent and product participate in the reaction:
- CuSO₄: 1 moles* 160 g/mole= 160 g
- Zn: 1 mole* 65.37 g/mole= 65.37 g
- Cu: 1 mole* 63.54 g/mole= 63.54 g
- ZnSO₄: 1 mole* 161.37 g/mole= 161.37 g
Now you can apply the following rule of three: if 160 grams of CuSO₄ react with 65.37 grams of Zn by this reaction stoichiometry, 454 grams of CuSO₄ with how much mass of Zn will it react?

mass of Zn= 185.49 grams
<u><em>185.49 grams of Zinc would react with 454g (1lb) of copper sulfate</em></u>
Answer:
The correct matching of the air mass and the letters in the word bank are given as follows;
1. Warm and humid ↔ D
2. Extremely cold and dry ↔ B
3. Cold and dry ↔ A
4. Cold and humid ↔ C
5. Warm and dry ↔ E
Where;
A Represents continental polar
B Represents Artic
C Represents Maritime Polar
D Represents Maritime Tropical
E Represents Continental Tropical
Explanation:
A. A continental polar is one that can be described as a cold and dry climate as the region is located at a further away from the oceanic water bodies that add humidity to the climate
B. The regions of the Artic and the Antarctic have very limited amount of precipitation every year because the air is very cold as well as dry
C. A polar climate is a cold climate region, while a maritime climate is humid.
Therefore, the maritime polar climate combines both cold and humid conditions
D. A warm and humid region has high rainfall and humidity, as such the maritime climate which are humid and the tropical climate, which are warm, combine to give a warm and humid climate
E. The continental tropical climate can be described as warm and dry, compared to the continental water bodies, due to the location being distant from and therefore, the absence of high moisture containing wind that comes from the oceans.
Explanation:
Bernoulli equation for the flow between bottom of the tank and pipe exit point is as follows.
= 
![\frac{(100 \times 144)}{62.43} + 0 + h[tex] = [tex]\frac{(50 \times 144)}{(62.43)} + \frac{(70)^{2}}{2(32.2)} + 0 + 40 + 60](https://tex.z-dn.net/?f=%5Cfrac%7B%28100%20%5Ctimes%20144%29%7D%7B62.43%7D%20%2B%200%20%2B%20h%5Btex%5D%20%3D%20%5Btex%5D%5Cfrac%7B%2850%20%5Ctimes%20144%29%7D%7B%2862.43%29%7D%20%2B%20%5Cfrac%7B%2870%29%5E%7B2%7D%7D%7B2%2832.2%29%7D%20%2B%200%20%2B%2040%20%2B%2060)
h = 
= 60.76 ft
Hence, formula to calculate theoretical power produced by the turbine is as follows.
P = mgh
= 
= 6076 lb.ft/s
= 11.047 hp
Efficiency of the turbine will be as follows.
=
× 100%
=
= 52.684%
Thus, we can conclude that the efficiency of the turbine is 52.684%.