1) HOBr stands for hypobromous acid. On reacting with water, products formed are OBr- and H3O+. Following reaction occurs during this process.
<span> HOBr + H2O </span>⇄<span> OBr- + H3O+
2) HOBr is a weak acid and have a lower value of dissociation constant (Ka ~ </span><span>2.3 X 10^–9). Hence, </span><span> large number of undissociated HOBr molecules are left in solution, when the reaction is completed/reaches equilibrium.</span>
11.0 kg = (11.0 kg)(1000 g/kg) = 11000 g
(11000 g)/(1400 cm3) = 7.857 g/cm3
Simplified = 7.86 g/cm3
I would say C. petroleum
A is wrong
B is impractical for "mainly used"
D thats too expensive
Answer:
Explanation:
AgNO3 + NaCl --> AgCl + NaNO3
Number of moles
AgNO3
= molar concentration * volume
= 1 * 0.01
= 0.01 mol
NaCl
= 0.01 * 1
= 0.01 mol.
By stoichiometry, 1 mole of silver nitrate reacted with 1 mole of NaCl. Therefore,
Number of moles of AgCl formed = 0.01 × 1
= 0.01 mol AgCl formed.
Heat absorbed by solution during precipitation:
Mass of solution = density × total volume
= 1 × 20
= 20 g.
q = m * Cp * (T2 - T1)
= 20 * 4.18 * (32.6 - 25.0)
= 635 J
Since 635 J was absorbed by the solution, the reaction released -635 J
So, Delta H = -635 J/0.01 mol
= -63500 J/mol
= -63.5 kJ/mol.
