Answer:
S is the limiting reagent.
Explanation:
To find the limiting reactant we must first write the balanced chemical reaction. It must be correctly balanced so that we can find the proper mole ratios.
2 S (s) + 3 O2 (g) + 4 NaOH (aq) → 2 Na2SO4 (aq) + 2 H2O (l)
After this we will convert our measurements to moles. For mass we do this by dividing by the molar mass.
2g ÷ 32.06 = 0.06238mol S
3g ÷ 32.00 = 0.09375mol O₂
Now that we have the moles of each of the reactants, we can multiply them by their mole ratio with a reactant.
0.06238mol S × 2/2 = 0.06238mol H2O
0.09375mol O₂ × 2/3 = 0.06250mol H2O
S is our limiting reagent because it makes the smaller amount of moles.
Answer:
The meaning and usefulness of the mole Page 2 2 • One mole of NaCl contains 6.022 x 1023 NaCl formula units. Use the mole quantity to count formulas by weighing them.
4 x 
in dL will be 4 x 
<h3>Conversion from dL to cm^3</h3>
Recall that:
Deci =
Centi = 
Thus, 1 dl = 100 ml
This means that converting from dl to requires multiplying by 
.
Applying this principle, 4 x in dL to will be:
4 x x = 4 x
Therefore, 4 x dl will be 4 x
More on volume conversion can be found here:
#SPJ1
its 640 because 150 goes into 900 6.4 times do you multiply 6.4 and 100 which is 640.
Answer:
NaHCO3 + HCl = NaCl + H2O + CO2
Explanation:
The total number of atoms of each element on either side of the equation must be equal.
