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krok68 [10]
3 years ago
13

How many grams of Aluminum are needed to produce 45.3 grams of Iron metal?

Chemistry
1 answer:
Dimas [21]3 years ago
3 0
It might be 90.6g...
You might be interested in
Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium ch
barxatty [35]

Answer: 353.6 g.


Explanation:


1) Word equation (given)

Sodium phosphate + calcium choride → sodium chloride + calcium phosphate


2) Balanced chemical equation

2 Na₃PO₄ +3 CaCl₂ → 6 NaCl + Ca₃(PO4)₂


3) Mole ratio

2 moles Na₃PO₄ : 3 moles CaCl₂ :  6 moles NaCl : 1 mole Ca₃(PO4)₂


4)  Formula to convert grams to moles

number of moles = mass in grams / molar mass


5) Number of moles of limiting reactant

a) mass in grams = 379.4 g CaCl₂

b) molar mass CaCl₂ = 110.98 g/mol

c) number of moles CaCl₂ = 379.4 g / 110.98 g/mol = 3.419 moles


6) Theoretical yield of Ca₃(PO4)₂

    3 moles CaCl₂ / 1 mole Ca₃(PO4)₂ = 3.419 moles CaCl₂ / x ⇒

    x = 3.419 × 1 / 3 = 1.140 moles Ca₃(PO4)₂


7) Convert 1.140 moles Ca₃(PO4)₂

a) molar mass Ca₃(PO4)₂ = 310.1767 g/mol

b) mass in grams = number of moles × molar mass = 1.140 moles × 310.1767 g/mol = 353.6 g ← answer.

7 0
3 years ago
can anyone help me with this and if my score is perfect i will brainlist u and follow you and please the answer must be the righ
mario62 [17]

Answer:

1.CL

2.SP

3.CL

4.SL

5.SL

6.SP

7.SL

8.CL

9.SL

10.CL

Explanation:

HOPE ITS HELP

5 0
3 years ago
Which type of organism helps return nutrients from dead plants and animals to the soil. A producer. B prey. C predator. D decomp
Gnom [1K]
The answer is D. Decomposer
8 0
3 years ago
Read 2 more answers
What is the Mechanical advantage of a machine that only changes the direction of the force?
Sloan [31]

Answer: 1

Explanation:

The number of times a machine increases a force exerted on it The input force will be the same as the output force.

6 0
3 years ago
* The cost of table salt and table sugar is Rs 15 per kg.
Vilka [71]

Cost per mole

Table salt : Rs 0.878

Table sugar : Rs 23.63

<h3>Further explanation</h3>

Given

Cost table salt (NaCl) = 15/kg

Cost table sugar(sucrose-C12H22O11) = 69/kg

Required

cost per mole

Solution

mol of 1 kg Table salt(NaCl ,MW= 58.5 g/mol) :

\tt mol=\dfrac{1000~g}{58.5}=17.09~mol=Rs~15\rightarrow 1~mol=Rs~0.878

mol of 1 kg Table sugar(C12H22O11 ,MW= 342 g/mol) :

\tt mol=\dfrac{1000}{342}=2.92~mol=Rs~69\rightarrow 1~mol=Rs~23.63

6 0
2 years ago
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