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3 years ago

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How many grams of Aluminum are needed to produce 45.3 grams of Iron metal?

1 answer:

Dimas [21]3 years ago

3 0

It might be 90.6g...

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013 10.0 points

34kurt

Answer:

this isn't immediately clear, it can be seen in ... CO2? 1. 6.0 × 10−23 g. 2. 44 g. 3. 7.31 × 10−23 g correct. 4. 6.0 × 10. 23 g. 5. 7.31 × 10 ... 40.0 grams of S will react leaving 10.0 grams. S unreacted. 013. 10.0 points ... FeCl2 and K2CO3 is ... 9. 1. There is no reaction. 2. KCl electrolyte. 3. CO2 gas. 4. FeCO3 precipitate. correct.

Explanation:

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3 years ago

E the table below for the next three questions.

Sliva [168]

Answer:

Explanation:i would go wit d

6 0

3 years ago

What type of reaction is represented in the following example?

Nikitich [7]

Answer:

endothermic

Explanation:

the negative sign of the heat indicates that heat is being drawn into the system, thus endothermic

3 0

4 years ago

Read 2 more answers

The introduction of synthetic fertilizers and chemical pesticides to farming date back to the __________

laiz [17]

Answer:

Humans started to use pesticides dating back to before 2000 BC.

Hope this helps ^-^

Explanation:

4 0

3 years ago

If you have a 150-gram sample of CrO3: • How many moles of CrO3 do you have? • How many oxygen atoms do you have? • How many gra

docker41 [41]

Answer :

(a) The moles of $CrO_3$ is, 1.5 moles.

(b) The number of oxygen atoms are, $27.099\times 10^{23}$

(c) The mass of oxygen is, 72 grams.

Explanation : Given,

Mass of $CrO_3$ = 150 g

Molar mass of $CrO_3$ = 100 g/mole

Molar mass of oxygen = 16 g/mole

(a) First we have to calculate the moles of $CrO_3$ .

$\text{Moles of }CrO_3=\frac{\text{Mass of }CrO_3}{\text{Molar mass of }CrO_3}=\frac{150g}{100g/mole}=1.5moles$

The moles of $CrO_3$ is, 1.5 moles.

(b) Now we have to calculate the number of oxygen atoms.

In $CrO_3$ , there are 1 atom of chromium and 3 atoms of oxygen.

According to the mole concept,

1 mole of $CrO_3$ contains $3\times 6.022\times 10^{23}$ number of oxygen atoms.

So, 1.5 mole of $CrO_3$ contains $1.5\times 3\times 6.022\times 10^{23}=27.099\times 10^{23}$ number of oxygen atoms.

The number of oxygen atoms are, $27.099\times 10^{23}$

(c) Now we have to calculate the mass of oxygen.

As, 1 mole of $CrO_3$ contains 3 moles of oxygen

So, 1.5 mole of $CrO_3$ contains $1.5\times 3=4.5$ moles of oxygen

$\text{Mass of oxygen}=\text{Moles of oxygen}\times \text{Molar mass of oxygen}$

$\text{Mass of oxygen}=(4.5mole)\times (16g/mole)=72g$

The mass of oxygen is, 72 grams.

3 0

3 years ago