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Eduardwww [97]
3 years ago
13

Please help me find the area of the shaded part

Mathematics
1 answer:
AURORKA [14]3 years ago
6 0
First you have Define the area of the total shape. Next you'd have to find the area of the unshaded shapes. then you would multiply in that area by floor because there for unshaded boxes. finally you subtract each box from the total area to get an answer of 3x - 4
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James usually drinks 38 ounces of water per day. He read that he should drink 64 ounces of water per day. If he starts drinking
vova2212 [387]
Answer at very bottom of picture above

if explanation need comment

7 0
3 years ago
What is the median of the data set? <br> {10, 15, 14, 14, 10, 10, 8, 18, 11, 12, 17, 16}
Alexus [3.1K]
The median of a data set is the 'middle number'. You can find the median by listing the given numbers from least to greatest (left to right) and finding the middle number.

8, 10, 10, 10, 11, 12, 14, 14, 15, 16, 17, 18

Cross one out on each side before getting to your last number that should be in the middle. 

The middle numbers are: 12 and 14. If it was only one number, we could already have the answer, but since it is two numbers in the middle, we need to add them up and divide by 2. 

12 + 14 = 26
26 ÷ 2 = 13

So, the median of the data set is: 13.
6 0
3 years ago
Type the expressions as radicals.<br> Y^5/2
Lapatulllka [165]

Answer:

it will be square root y^5

Step-by-step explanation: Apply the rule x m/n=n√x m to rewrite the exponentiation as a radical.

7 0
3 years ago
What digit has the thousandths value in two hundred forty-six ten thousandths? *
Fed [463]
The answer is D, 10 is in the thousandths place
8 0
3 years ago
Read 2 more answers
The value of x in the equation log(x-1)9=2 is
mel-nik [20]
\log_{(x-1)} 9=2

the domain:
x-1 >0 \ \land \ x-1 \not=1 \\&#10;x>1 \ \land \ x \not= 2 \\&#10;x \in (1; 2) \cup (2;+\infty)

the equation:
\log_{(x-1)}9=2 \\&#10;(x-1)^2=9 \\&#10;\sqrt{(x-1)^2}=\sqrt{9} \\&#10;|x-1|=3 \\&#10;x-1=3 \ \lor \ x-1=-3 \\&#10;x=4 \ \lor \ x=-2

4 is in the domain
-2 is not in the domain

The answer:
x=4

***
Also, the answer in 13 is {8}. -3 is not in the domain. Replace x with -3 and you'll see:
x=\sqrt{5x+24} \\&#10;-3=\sqrt{5 \times (-3)+24} \\&#10;-3=\sqrt{-15+24} \\&#10;-3=\sqrt{9} \\&#10;-3=3
It's not true so -3 isn't a solution to this equation.
4 0
3 years ago
Read 2 more answers
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