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navik [9.2K]
3 years ago
5

When density increases, what happens to the number of molecules in a volume of air?

Physics
1 answer:
solniwko [45]3 years ago
5 0

When density increases the number of molecules stay the same, im not entirely sure but i hope its right.

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Does anyone know? Please help! Thank you!
Vedmedyk [2.9K]

B density will increase

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3 years ago
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Which of the following is a good step in learning how to manage time?
Luden [163]
I think is c because your seeing how your using you’re time.
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3 years ago
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In example 18. 4 of the text, the deflection angle of the laser beam as it exits the prism is 22. 6º. If the prism had been made
Marrrta [24]

The deflection angle is 37.29º if the prism was made of polystyrene plastic.

What is a laser beam?

Laser beam is a light beam propagating dominantly in one direction.

It is a beam of radiation produced from a laser.

Here given that,

refraction index of glass, n1= 1.52

refraction index of polystyrene plastic, n2 = 1.59

deflection angle, B = 22.6º

For the second surface,

B  = 45º - 22.6º

B  = 22.40º

Now from the formula of Snell's law:

n1 sinФ = n2 sin B

sin B / sinФ = n1 / n2

sinФ = (sin 22.40º) * ( 1/ 1.59)

Ф = 37.29º

Hence,

The deflection angle is 37.29º if the prism was made of polystyrene plastic.

Learn more about laser beam here:

<u>brainly.com/question/4218151</u>

#SPJ4

3 0
2 years ago
Characteristics of saturn
Tresset [83]

Saturn is a planet in solar system. It's ring is made out of small covered ice particle. It has over 30 moons.

3 0
3 years ago
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What temperature increase is necessary to increase the power radiated from an object by a factor of 8?
Aleks04 [339]

To solve this problem it is necessary to apply the concepts related to the Power defined from the Stefan-Boltzmann equations.

The power can be determined as:

P = \sigma T^4

Making the relationship for two states we have to

\frac{P_1}{P_2} = \frac{T_1^4}{T_2^4}

Since the final power is 8 times the initial power then

P_2 = 8P_1

Substituting,

\frac{1}{8} = \frac{T_1^4}{T_2^4}

T_2 = T_1 8*(\frac{1}{4})

T_2 = 1,68T_1

The temperature increase would then be subject to

\Delta T = T_2-T_1

\Delta T = 1.68T_1 -T_1

\Delta T = 0.68T_1

The correct option is D, about 68%

7 0
3 years ago
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