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Romashka [77]
3 years ago
11

Now assume that the water is contained in a 0.1-kg aluminum pot (cAl = 900 J/kg-K) that is initially at 293 K just like the wate

r. How much energy must be transferred into the pot-and-water system in order to raise its temperature to the boiling point of water?
Physics
1 answer:
Tpy6a [65]3 years ago
7 0

The energy transferred into the pot and water system in  order to raise its temperature to the boiling point of water is Q = 7213.5 J.

<u>Explanation:</u>

The thermal energy is transferred from one object to another with a  temperature difference is called heat and it is measured in joules (J). This is because heat is a transfer of energy.

The energy moves from the hotter object to the colder object during the energy transfer whereas the hotter object gets cooled and the colder object gets warmed up.  

(The boiling point of water is 373.15 K)

The energy transferred is given by the formula,

Q = mass of Pot * Specific Heat of Aluminum * ( 373.15 - 293 )

Q = 0.1 * 900 * 80.15

Q = 7213.5 J    

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Answer:

  Natalie says that all things with mass have a gravitational field, but the force is very weak and cannot be perceived around small objects.

Explanation:

The force due to gravity is proportional to the mass of the object and inversely proportional to the square of the distance between objects. The Earth is so massive that the force due to its gravity is much greater than the force between objects on the counter.

If there were no friction, the objects might move toward each other, depending on what other masses were near them tending to cause them to move in other directions.

Natalie's explanation is about the best.

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<em>Additional comment</em>

The universal gravitational constant was determined by Henry Cavendish in the late 18th century using lead balls weighing 1.6 pounds and 348 pounds. His experiment was enclosed in a large wooden box to minimize outside effects. While these masses are somewhat greater than those of a glue bottle and stapler, the experiment shows the force of gravity between "small" objects <em>can</em> be measured.

8 0
3 years ago
A parallel-plate capacitor has square plates that have edge length equal to 1.20×102cm and are separated by 1.00 mm. It is conne
lora16 [44]

Answer:

Energy stored in the capacitor will be 1.835\times 10^{-6}J

Explanation:

We have given edge length of capacitor = 1.2\times 10^2cm=1.2m

So area A = 1.2×1.2 = 1.44 m^2

Separation is given as d  1 mm = 10^{-3}m

We know that capacitance is given by C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 1.44}{10^{-3}}=12.744\times 10^{-9}F

Voltage is given as V = 12 volt

We know that energy stored is given by E=\frac{1}{2}CV^2=\frac{1}{2}\times 12.744\times 10^{-9}\times 12^2=1.835\times 10^{-6}J

3 0
3 years ago
Read 2 more answers
If a system has 225 kcal of work done to it, and releases 5.00 × 102 kj of heat into its surroundings, what is the change in int
vovikov84 [41]

We can solve the problem by using the first law of thermodynamics:

\Delta U = Q-W

where

\Delta U is the change in internal energy of the system

Q is the heat absorbed by the system

W is the work done by the system on the surrounding


In this problem, the work done by the system is

W=-225 kcal=-941.4 kJ

with a negative sign because the work is done by the surrounding on the system, while the heat absorbed is

Q=-5 \cdot 10^2 kJ=-500 kJ

with a negative sign as well because it is released by the system.


Therefore, by using the initial equation, we find

\Delta U=Q-W=-500 kJ+941.4 kJ=441.4 kJ

8 0
3 years ago
A ball on a cart is moving at a rate of 2 m/s. The cart suddenly stops and the ball continues to travel in the same direction at
sukhopar [10]

Answer:

The first

Explanation:

Cause it will continue in motion till another force is applied

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A large volume of the solar system's space is occupied by what?
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Junk from our atmosphere
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