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3 years ago

The sum of 5 consecutive odd numbers is 505

Mathematics

1 answer:

pentagon [3]3 years ago

8 0

Answer:

In a sequence of 5 numbers, the 3rd number is the middle number. So in your problem the third number is the average of the 5 numbers -- which is the sum of the numbers, divided by how many there are: 505/5 = 101.

Explanation:

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3 years ago

Which is smaller: an angle showing a turn through 1/8 of a circle or an angle showing a turn through 1/3 of a circle? Explain yo

Zolol [24]

Answer:

An angle showing a turn through 1/8 of a circle is smaller

Step-by-step explanation:

we know that

A complete circle represent 360°

An angle showing a turn through 1/8 of a circle is

$(360\°)*(\frac{1}{8})=45\°$

An angle showing a turn through 1/3 of a circle is

$(360\°)*(\frac{1}{3})=120\°$

therefore

An angle showing a turn through 1/8 of a circle is smaller

5 0

4 years ago

What are the multiples of 6 through 100

bulgar [2K]

6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,

5 0

3 years ago

Read 2 more answers

Solve each equation by completing the square. If necessary, round to the nearest hundredth.

Ksenya-84 [330]

$1.)\\ \\ b^2+10b=75\\ \\ b^2+10b-75=0\\ \\\Delta = b^{2}-4ac = 10^{2}-4*1*(75)=100+300=400 \\ \\\sqrt{\Delta }=\sqrt{400}=20$

$b_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-10-20}{2}=\frac{-30}{2}=-15\\ \\b_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-10+20}{2}=\frac{10}{2}=5$

$2.)\\ \\ n^2-20n=-75\\ \\ n^2-20n+75=0\\ \\\Delta = b^{2}-4ac = (-20)^{2}-4*1*75=400-300=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$n_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{20-10}{2}=\frac{10}{2}=5\\ \\n_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{20+10}{2}=\frac{30}{2}=15$

$3.)\\ \\t^2+8t-9=0\\ \\\Delta = b^{2}-4ac = 8^{2}-4*1* (-9)=64+36=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$t_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-8-10}{2}=\frac{-18}{2}=-9\\ \\t_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{-8+10}{2}=\frac{2}{2}=1$

$4.)\\ \\m^2-2m-8=0\\ \\\Delta = b^{2}-4ac = (-2)^{2}-4*1* (-8)=4+32=36\\ \\\sqrt{\Delta }=\sqrt{36}=6$

$m_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{2-6}{2}=\frac{-4}{2}=-2\\ \\m_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{2+6}{2}=\frac{8}{2}=4$

$5.)\\ \\ v^2+4v-2=0\\ \\\Delta = b^{2}-4ac = 4^{2}-4*1* (-2)=16+8=24\\ \\\sqrt{\Delta }=\sqrt{24}= \sqrt{4*6}=2\sqrt{6}$

$v_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-4-2\sqrt{6}}{2}=\frac{2(-2-\sqrt{6}}{2}= -2-\sqrt{6}\approx -2-2,45\approx -4,45\\ \\v_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{-4+2\sqrt{6}}{2}=\frac{2(\sqrt{6}-2}{2}= \sqrt{6}-2 \approx 2,45-2\approx 0,45$

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3 years ago

What is the discriminant of the quadratic equation 0 = –x2 + 4x – 2? –4 8 12 24

monitta

Answer:

Step-by-step explanation:

0 = –x^2 + 4x – 2

This is of the form

ax^2 +bx +c

a = -1 b = 4 x = -2

The discriminant is

b^2 -4ac

4^2 - 4(-1)(-2)

16 - 8

6 0

3 years ago

Read 2 more answers