How do you get the height of a square based prism if the total surface area is 990 cm2 and the area of the base is 121cm2.
1 answer:
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Answer:
There is a linear correlation between chest size and weight,0.8482
Step-by-step explanation:
Given that for a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears.
the value of the linear correlation coefficient is r = 0.921.
i.e. there is a strong positive correlation from the value of r.
(Two tailed test at 5% level for correlation coefficient)
Test statistic t =
p value <0.00001
Since p is less than 0.05 we reject H0
a) There is a linear correlation between chest size andweight
b)-- R^2 = 0.8482 proportion of the variation in weight can be explainedby the linear relationship between weight and chest size
The maximum height of the rocket is 43.89 feet
<h3>How to write the function</h3>The general function is given as:
h(t) = -16t^2 + vt + h
The initial velocity is
v = 53
So, we have:
h(t) = -16t^2 + 53t + h
The initial height is
h = 0
So, we have:
h(t) = -16t^2 + 53t
Hence, the function of the height is h(t) = -16t^2 + 53t
<h3>The maximum height of the rocket</h3>
In (a), we have:
h(t) = -16t^2 + 53t
Differentiate the function
h'(t) = -32t + 53
Set to 0
-32t + 53 = 0
This gives
-32t = -53
Divide by -32
t = 1.65625
Substitute t = 1.65625 in h(t) = -16t^2 + 53t
h(1.65625) = -16 * 1.65625^2 + 53 * 1.65625
Evaluate
h(1.65625) = 43.890625
Approximate
h(1.65625) = 43.89
Hence, the maximum height of the rocket is 43.89 feet
<h3>Time to hit the ground</h3>In (a), we have
h(t) = -16t^2 + 53t
Set to 0
-16t^2 + 53t = 0
Divide through by -t
16t - 53 = 0
Add 53 to both sides
16t = 53
Divide by 16
t = 3.3125
Hence, the time to hit the ground is 3.3125 seconds
<h3>The graph of the function h(t)</h3>See attachment for the graph of the function h(t)
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