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jasenka [17]
3 years ago
9

The sum of the squares of two consecutive positive odd integers is 202. Find the numbers. Let statement and algebraic solution p

lease. Thanks!
Mathematics
1 answer:
slega [8]3 years ago
5 0

Answer:

ysbbs

Step-by-step explanation:

gebsjsjsisisuisiddd

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5x - (x + 3)= 1/3 (9x + 18) - 5
telo118 [61]
1/3(9x) =3x
1/3(18) =6

3x+6-5

Then you do
-(x)=-x
-(3)=-3

5x-x-3 = 4x-3

4x-3=3x+6-5
4x-3=3x+1

x=4
4 0
3 years ago
Read 2 more answers
Can someone help me please
Neporo4naja [7]

If Deliah does jumping jacks at a constant rate, this means that she does them at the same pace or you could say that she does the same amount of jumping jacks in a specified amount of time, ie. if you counted how many jumping jacks she did in one minute, it would be same as how many she would complete in the next minute, and the next, and so on.

Now given that she does 184 jumping jacks in four minutes, and she has kept a constant pace throughout, to find out how many she does each minute, we simply need to divide the number of jumping jacks she does in 4 minutes by 4. Thus:

Jumping jacks in 1 minute = Jumping jacks in 4 minutes / 4

= 184 / 4

= 46

Thus, Deliah can do 46 jumping jacks per minute.

5 0
3 years ago
Help plzzzz and tysm <3. I love you all but plz do this asap! Thank you like againnn, take you’re time!
malfutka [58]

Answer:

1.12+36=48.

2)125-25=100

3)5+100=105

4)64-30=34

7 0
3 years ago
Read 2 more answers
What is the value of u ?
nasty-shy [4]

Answer:

u = 47

I would explain but some people can't read

8 0
2 years ago
Read 2 more answers
In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=4 and BC=3, Find AH, CH and BH.
IRISSAK [1]

Answer:

  • AH = 3.2
  • CH = 1.8
  • BH = 2.4

Step-by-step explanation:  

It can be convenient to compute the length of the hypotenuse of this triangle (AC). The Pythagorean theorem tells you ...

   AC^2 = AB^2 + CB^2

   AC^2 = 4^2 + 3^2 = 16 + 9 = 25

   AC = √25 = 5  

The altitude divides ∆ABC into similar triangles ∆AHB and ∆BHC. The scale factor for ∆AHB is ...

  scale factor ∆ABC to ∆AHB = AB/AC = 4/5 = 0.8  

And the scale factor to ∆BHC is ...  

  scale factor ∆ABC to ∆BHC = BC/AC = 3/5 = 0.6  

Then the side AH is 0.8·AB = 0.8·4 = 3.2

And the side CH is 0.6·BC = 0.6·3 = 1.8  

These two side lengths should add to the length AC = 5, and they do.  

The remaining side BH can be found from either scale factor:    

  BH = AB·0.6 = BC·0.8 = 4·0.6 = 3·0.8 = 2.4

_____  

The sides of interest are ...  

  AH = 3.2

  CH = 1.8

  BH = 2.4

3 0
3 years ago
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