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3 years ago

Convert the following angle measures to radians. Give answers to the nearest hundredth of a radian.

Mathematics

1 answer:

tester [92]3 years ago

4 0

Answer:

0.56 and 2.97

Step-by-step explanation:

to convert from degree to radian measure

radian = degree measure × $\frac{\pi }{180}$

(1)

32 × $\frac{\pi }{180}$ = 0.56 ( nearest hundredth )

(2)

170 × $\frac{\pi }{180}$ = 2.97 ( nearest hundredth )

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Help me solve for q! 21 + 3q < 3 (13 - q) How do you solve it? Thank you!

Molodets [167]

Good morning

21 + 3q < 3(13 - q)
21+ 3q < 39 - 3q Here it was -3q and it was on the left side. However when you are switching it to another terms that looks like it you must change the sign as well.
3q + 3q < 39 - 21 Here I bring the common terms together.
6q < 18
Divide both sides by 6
6q/6 < 18/6
q < 3

8 0

3 years ago

The cost price of a box and a pen is Rs 120. The box is sold at 10% profita the pen is sold at 10% loss. If the selling price of

matrenka [14]

Answer:

3.803% Profit

Step-by-step explanation:

First let us calculate total sales, then calculate the total cost, and then divide the two.

Sale: 120*1.1=132 and 52*.9=46.8

Cost: 120 and 52

Profit equation:

$\frac{Net sales-COGS}{Net Sales} =Profit$

$\frac{(132+46.8)-(120+52)}{(132+46.8)}$

Simplify:

$\frac{6.8}{178.8} =.03803$ or 3.803% Profit

5 0

3 years ago

Find the value of each of the following: exponents

Nataly [62]

Answer:

7) is 625

8) 169

9) 1.44

10) 180??

11) 1000000

12) 3430

hopefully these are right

Step-by-step explanation:

7 0

2 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$