Answer:
I need the graph
Step-by-step explanation:
51) 5x-1=0 and x+6=0
5x=1, x=1/5 and x=-6
2 solutions x=1/5 and x=-6
52)x(2x+3)=0
2x=0 and 2x+3 =0
x=0 and x=-3/2=-1.5
53) x(5x-1)=0
x=0 and 5x-1=0
x=0 and x=1/5
54) z(4z+7) =0
z=0 and 4z+7=0
z=0 and z= - 7/4 = -1.75
z=0 and z=-1.75
<span>625(5xy)^-3/ (5x)^2 y^7
625
= -------------------- / 25x^2y^7
125 x^3y^3
= 5/x^3y^3 / </span>25x^2y^7
= 5/x^3y^3 * (1/ 25x^2y^7)
= 1 / 5x^5y^10
answer
1
-----------------
5x^5y^10
F(x) = 6(9)^x
f(1/2) = 6(9)^(1/2)
f(1/2) = 6(9)^(0.5)
f(1/2) = 6*(9^0.5) 9^0.5 = √9 = +3 or -3.
f(1/2) = 6*3 = 18 or 6*-3 = -18
f(1/2) = 18 or -18
Hope this helps.
Answer:The obvious difference between substitution and elimination reactions is that substitution reactions replace one substituent with another while elimination reactions simply remove the substituent. ... The major difference between the groups is the number of steps the reaction takes place over.
Step-by-step explanation:
