The 6th term in the sequence should be 63
Step-by-step answer:
Please refer to attached image.
1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning
that
angles QPS and QRS are supplementary =>
QPS+QRS=180 =>
QRS = 180 - 74 = 106
2. Triangle RSQ is isosceles with RS=RQ =>
angles RSQ and RQS are congruent.
3. Angle RSQ = (180 - 106) /2 = 74 / 2 = 37
4. QP is a diameter => angle QSP is a right-angle.
5. From (3) and (4) above,
angle RSP = 37+90 = 127
6. Since PQRS is cyclic, angles RQP and RSP are supplementary =>
RQP+RSP = 180 =>
x + 127 = 180 =>
x = 180 - 127 = 53 degrees.
First symmetrically cut the pentagon to get 5 pieces. (So that you will get the idea that this polygon is divided into 5 triangles)
Then find the area of one of the triangles:
Area of Triangle = 
A =
× 4 × 10
A = 20 m²
To find the area of the whole pentagon shape:
A = 20 × 5 = 100 m²
<em>Hope it helps!</em>
Answer:
26 ft
Step-by-step explanation:
I'm guessing this is how it's done
60-40= 20
there for at this time any shadow would be 20x it's original height/length
so 6+20=26 ft
lmk if I'm correct
Answer:
<h2>Factors = (3x - 1) (2x - 1)</h2><h2>values :- x = 1/3 , 1/2</h2>
Step-by-step explanation:
= > 6x^2 + 1 = 5x
• Bring it in the standard form,
= > 6x^2 - 5x + 1 = 0
= > 6x^2 - (3 + 2)x + 1 = 0
= > 6x^2 - 3x - 2x + 1 = 0
• Take out common
= > 3x (2x - 1) - 1 (2x - 1) = 0
= > (3x - 1) (2x - 1) = 0...factors
= > x = 1/3 and 1/2... values of x
<h2>Hope it helps you!! </h2>