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Ainat [17]
2 years ago
12

What is the value of x?

Mathematics
1 answer:
9966 [12]2 years ago
3 0
<span>What is the approximate circumference of the circle? Use π ≈ 3.14. Circle A with radius 18 feet. 21.1 feet 36 feet 56.5 feet 113 feet PLZ help</span>
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I kinda forgot how to do things like 2 divided by 5. plz help​
pentagon [3]

Answer:

the answer 0.4

Step-by-step explanation;

4 0
2 years ago
13-8+3 evaluate using the Order of Operation
Novay_Z [31]

You would just subtract/add like you normally would from left to right because its a subtract and add operation.

Hope that helps :)

6 0
3 years ago
What is the remainder of 9263 divided by 88?
professor190 [17]

Answer:

105.26

Step-by-step explanation:

6 0
2 years ago
Jose Canseco hit three fifth-deck home runs at SkyDome/Rogers Centre during his career, including the first ever at the stadium
Mademuasel [1]

Answer:

187 ft/s

Step-by-step explanation:

Given in the y direction:

v₀ = 0 ft/s

Δy = 75 ft

a = 32 ft/s²

Find: t

Δy = v₀ t + ½ at²

(75 ft) = (0 ft/s) t + ½ (32 ft/s²) t²

t = 2.165 s

Given in the x direction:

Δx = 480 ft

a = 0 ft/s²

t = 2.165 s

Find: v₀

Δx = v₀ t + ½ at²

(480 ft) = v₀ (2.165 s) + ½ (32 ft/s²) (2.165 s)²

v₀ = 187 ft/s

4 0
2 years ago
!!Plz urgent help!!
Firdavs [7]

Answer:

890 beads can be fitted in the triangular prism.

Step-by-step explanation:

If we can fill the spherical beads completely in the triangular prism,

Volume of the triangular prism = Volume of the spherical beads

Volume of triangular prism = Area of the triangular base × Height

From the picture attached,

Area of the triangular base = \frac{1}{2}(\text{Base})(\text{Height})

                                             = \frac{1}{2}(AB)(BC)

By applying Pythagoras theorem in the given triangle,

AC² = AB² + BC²

(13)² = 5² + BC²

169 = 25 + BC²

BC² = 144

BC = 12

Area of the triangular base = \frac{1}{2}(5)(12)

                                             = 30 cm²

Height of the triangular prism = 18 cm

Volume of the triangular prism = 30 × 18

                                                   = 540 cm³

Volume of one spherical bead = \frac{4}{3}\pi r^{3}

                                                   = \frac{4}{3}\pi (0.525)^{3}

                                                   = 0.606 cm³

Let there are 'n' beads in the triangular prism,

Volume of 'n' beads = Volume of the prism

540 = 0.606n

n = 890.90

n ≈ 890

Therefore, 890 beads can be fitted in the triangular prism.

3 0
2 years ago
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