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Ainat [17]
3 years ago
12

What is the value of x?

Mathematics
1 answer:
9966 [12]3 years ago
3 0
<span>What is the approximate circumference of the circle? Use π ≈ 3.14. Circle A with radius 18 feet. 21.1 feet 36 feet 56.5 feet 113 feet PLZ help</span>
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According to the CDC, the rate of Cesarean births in the United States in 2013 was about 33%. Suppose a random sample of 200 bir
sergij07 [2.7K]

Answer:

n = 200

p = 0.33.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

33% of the births are Cesarean, so p = 0.33

Sample of 200 births, which eans that, n = 200

7 0
3 years ago
Write a paragraph proof that 1+1=2<br> (Fun fact: it took over 72 pages just to prove that 1+1=2)
Irina18 [472]

Answer:

The theorem here is essentially that

if a and 3 are disjoint sets with

exactly one element each, then their

union has exactly two elements. ...

Peano shows that it's not hard to

produce a useful set of axioms that

can prove 1+1=2 much more easily

than Whitehead and Russell do.

3 0
3 years ago
Read 2 more answers
What is the awnser.i don't get it.
Dennis_Churaev [7]
8x+Y=-16
answer
Y=-8x-16
6 0
3 years ago
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Which value of n makes this equation true?
jonny [76]

Answer:

the answer is A. -16

Step-by-step explanation:

3(-16)+3= -45

-45/5=

-9

5(-16)-1=-81

-81/9=

-9

-9=-9

4 0
3 years ago
In a right triangle, CosA=0.352 and SinA=0.936 What is the approximate value of tanA?
mr_godi [17]
\tan A=\frac{\sin A}{\cos A}

Proof: \sin\div\cos=\frac{o}h\div\frac{a}h=\frac{o}h\times\frac{h}a=\frac{oh}{ha}=\frac{o}a=\tan

\cos A=0.352,\ \sin A=0.936

\tan A=\frac{0.936}{0.352}

\boxed{\tan A=2.65\overline{90}} <em>(round as needed)</em>
6 0
3 years ago
Read 2 more answers
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