Answer:
the answer 0.4
Step-by-step explanation;
You would just subtract/add like you normally would from left to right because its a subtract and add operation.
Hope that helps :)
Answer:
105.26
Step-by-step explanation:
Answer:
187 ft/s
Step-by-step explanation:
Given in the y direction:
v₀ = 0 ft/s
Δy = 75 ft
a = 32 ft/s²
Find: t
Δy = v₀ t + ½ at²
(75 ft) = (0 ft/s) t + ½ (32 ft/s²) t²
t = 2.165 s
Given in the x direction:
Δx = 480 ft
a = 0 ft/s²
t = 2.165 s
Find: v₀
Δx = v₀ t + ½ at²
(480 ft) = v₀ (2.165 s) + ½ (32 ft/s²) (2.165 s)²
v₀ = 187 ft/s
Answer:
890 beads can be fitted in the triangular prism.
Step-by-step explanation:
If we can fill the spherical beads completely in the triangular prism,
Volume of the triangular prism = Volume of the spherical beads
Volume of triangular prism = Area of the triangular base × Height
From the picture attached,
Area of the triangular base = 
= 
By applying Pythagoras theorem in the given triangle,
AC² = AB² + BC²
(13)² = 5² + BC²
169 = 25 + BC²
BC² = 144
BC = 12
Area of the triangular base = 
= 30 cm²
Height of the triangular prism = 18 cm
Volume of the triangular prism = 30 × 18
= 540 cm³
Volume of one spherical bead = 
= 
= 0.606 cm³
Let there are 'n' beads in the triangular prism,
Volume of 'n' beads = Volume of the prism
540 = 0.606n
n = 890.90
n ≈ 890
Therefore, 890 beads can be fitted in the triangular prism.