Well
It is in the form of a/b + b/a = (a sqr + b sqr)ab
Substitute
(Sin sqr theta + cos sqr theta) +2 cos theta + 1. 2 + 2cos theta
———————————————————————— = ————————-
Sin theta(1+cos theta). Sin theta (1 + cos theta)
2(1+ cos theta)/sin theta(1 + cos theta). {1 + cos theta cancelled}
2/sin theta. Hope it helps :}
Intersection (repeated element in the set)
A={-9,0,5}
B={0,2,5,8}
C={-9,2,5}
Ans: C, {5}
*In set B and C, element 2 was repeated but not for set A.
They forget to say "not to scale". I'm guessing this is trig because I don't see another way to do it.
Let's consider x=chord PQ first. By the Law of Cosines
We have an isosceles triangle formed by two radii of 9 cm and x=PQ. By the Law of Cosines again,
The area of the circle is the fraction given by the angle,
Answer: 24.7 sq cm
Answer:
For an equal number of servings,the bananas will have three times as much sugar.
Step-by-step explanation:
If you would like me to explain how I got this answer, tell me in the comments
