The first equation is $3 times 9 = $27 the next equation iis $1 times 2 = $1
So you do 9 transactions over $100 and 2 transactions of $100 or lower.
From the figure the given line passes through the points (0, 0) and (-4, 8).
Recall that the equation of a straight line is given by

Thus, The equation of the given figure is given by
Answer:
<h2>The domain for this function is

where

.</h2>
Step-by-step explanation:
The given function is

Where
represents cars. This function models the profits they make.
Now, as you can deduct already, we can define to different domains, the mathematical one and the reasonable one.
The reasonable domain is about all the useful values to the problem. For example, as we are talking about car, they can't wash -5 cars, so negative numbers are excluded. Similarly, they can't wash 6.75 cars, because that would imply an incomplete job.
Therefore, the domain for this function is
where
.
(Notice that we specify that the independent valur can only use whole positive numbers only).
Answer:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.
Step-by-step explanation:
In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.
Let u = 1 + sin(x).
This means du/dx = cos(x). This implies dx = du/cos(x).
Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.
∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))
= ∫(u^(-1/2) * du). Integrating:
(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.
Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!
0.02/0.64*100=3.125℅
The formula is:(/error/divided by right answer) times 100. /means absolute value