What is the equation of the following line? Be sure to scroll down first to see all answer options.

Mathematics

1 answer:

Annette [7]3 years ago

8 0

From the figure the given line passes through the points (0, 0) and (-4, 8).

Recall that the equation of a straight line is given by
$\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}$

Thus, The equation of the given figure is given by
$\frac{y-0}{x-0} = \frac{8-0}{-4-0}= \frac{8}{-4} \\ \\ -4y=8x \\ \\ y=-2x$

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dangina [55]

$\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\qquad 
\begin{cases}
r=radius=\frac{diameter}{2}\\
h=height\\
----------\\
diameter=1.8\\
r=\frac{1.8}{2}=0.9\\
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\end{cases}\implies V=\pi \cdot 0.9^2\cdot 5\\\\
-------------------------------\\\\
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\\\\\\
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