A continuous length of wire is made into 10 coaxial loops, located in the plane of this page. Each loop has a cross sectional ar
1 answer:
Answer:
e = 10 V
Explanation:
given,
number of the coaxial loops = 10
Cross sectional area = 0.5 m²
magnitude of magnetic field =
B = 3 T + (2 T/s)*t.
B = ( 3+ 2 t ) T
induced potential difference = ?
At time = 2 s
we know,
induced emf
∅ = B . A
e = -10 V
magnitude of induced emf
|e| = |-10 V|
e = 10 V
the induced potential difference in the loop = e = 10 V
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Answer:
Explanation:
Given
Current in two wires
Magnetic Force per unit length is given by
where
r=radial distance between wires
Force on two wires will be equal in magnitudes but opposite in direction so Force on wire 1 duet o wire 2
Answer:
Explanation:
The energy for an isothermal expansion can be computed as:
--- (1)
However, we are being told that the volume of the gas is twice itself when undergoing adiabatic expansion. This implies that:
Equation (1) can be written as:
Also, in a Carnot engine, the efficiency can be computed as:
In addition to that, for any heat engine, the efficiency e =
relating the above two equations together, we have:
Making the work done (W) the subject:
From equation (1):
If we consider the adiabatic expansion as well:
= constant
i.e.
From ideal gas PV = nRT
we can have:
From the question, let us recall aw we are being informed that:
If the volumes changes by a factor = 5.7
Then, it implies that:
∴
In an ideal monoatomic gas
As such:
Replacing the value of into equation
From in the question:
W = 930 J and the moles = 1.90
using 8.314 as constant
Then:
From