Answer:
Explanation:
given,
op-amp circuit with a gain of = (Av₁) = 96 V/V
Band width = (Bw₁) = 8 kHz
Required bandwidth(Bw₂) = 32 kHz
Highest gain available =(Av₂) = ?
For the given system Bandwidth product is constant
Av₁ Bw₁ = Av₂ Bw₂
96 x 8 = Av₂ x 32
the highest gain available under these conditions
210J
PE is mgh in this context.
Answer:
1.) U = 39.2 m/s
2.) t = 4s
Explanation: Given that the
height H = 78.4m
The projectile is fired vertically upwards under the acceleration due to gravity g = 9.8 m/s^2
Let's assume that the maximum height = 78.4m. And at maximum height, final velocity V = 0
Velocity of projections can be achieved by using the formula
V^2 = U^2 - 2gH
g will be negative as the object is moving against the gravity
0 = U^2 - 2 × 9.8 × 78.4
U^2 = 1536.64
U = sqrt( 1536.64 )
U = 39.2 m/s
The time it takes to reach its highest point can be calculated by using the formula;
V = U - gt
Where V = 0
Substitute U and t into the formula
0 = 39.2 - 9.8 × t
9.8t = 39.2
t = 39.2/9.8
t = 4 seconds.
According to Newton's first law of motion, what happens to the ball is the ball rolls backward.
<h3>What is the first law?</h3>
This means that an object at rest or in motion will remain uniformly rectilinear and tend to be in that state if the net force on it is zero.
In this case, we have to think that the ball is at rest and the train is moving with a velocity that way, the reaction of the ball will be to go in the opposite direction to the motion.
See more about first law at brainly.com/question/3808473
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