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vichka [17]
3 years ago
9

in a group of people for every 20 people 7 of them have blue eyes a) write the ratio of the number of people with blue eyes to t

he total of people in fraction form b) if there are 100 total people how many how many of them have blue eye? explain how u found your answer
Mathematics
1 answer:
bazaltina [42]3 years ago
5 0

Answer:

a) 7 : 20

b)There will be 35 people with blue eye

Step-by-step explanation:

a)

This question is asking you the ratio of the number of people with blue eyes to the total number of people.

So seven people with blue eyes to the total number of 20 people.

7 : 20

b)

you got the ratio 7 : 20, this also means that there will be 7 people with blue eyes in every 20 people.

so you use 100 divides by 20, you will get the number five, this means there are 5 groups of 20 in 100 people.

so then you use 5 times 7, then you got the number 35.

That means, there are 35 people with blue eyes in 100 people.

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The sum of 4 consecutive even numbers is 36. What is the first number in this sequence?
sashaice [31]

Answer:

the first number in this sequence is 6....

Step-by-step explanation:

First number = x

2nd number = x+2

3rd consecutive even number = x+4

4th consecutive even number = x+6

Therefore,

By adding these numbers:

x+x+2+x+4+x+6= 36

Add the like terms:

4x+12=36

Combine the constants:

4x=36-12

4x=24

Divide both the terms by 4

4x/4 = 24/4

x= 6

Thus the first number in this sequence is 6....

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Two balls are drawn in succession out of a box containing 4 red and 3 white balls. Find the probability that at least 1 ball was
kifflom [539]

Answer:

A) 40/49

B) 36/42

Step-by-step explanation:

Given:

Red Balls, R : 4

White Balls, W : 3

Total Balls : 3+4=7 balls

A) If balls were replaced before the 2nd draw

P (White) = 3/7; P(Red) = 4

P(at least 1 red ball),

= 1 - P(no red balls)

= 1  - P(White, White)

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A) If balls were replaced before the 2nd draw

P(1st White Ball) = 3/7 ; P(2nd White Ball) = 2/6

P(at least 1 red ball),

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Answer:

13/4096

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The total number of possibilities for the free throws is 2^12 = 4096

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