Answer:
The order must be K2→K1, since the permanently active K1 allele (K1a) is able to propagate the signal onward even when its upstream activator K2 is inactive (K2i). The reverse order would have resulted in a failure to signal (K1a→K2i), since the permanently active K1a kinase would be attempting to activate a dead K2i kinase.
Explanation:
- You characterize a double mutant cell that contains K2 with type I mutation and K1 with type II
mutation.
- You observe that the response is seen even when no extracellular signal is provided.
- In the normal pathway, i f K1 activat es K2, we expect t his combinat ion of two m utants to show no response with or without ext racell ular signal. This is because no matt er how active K1 i s, it would be unable to act ivate a mutant K2 that i s an activit y defi cient. If we reverse the order, K2 activating K1, the above observati on is valid. Therefore, in the normal signaling pathway, K2 activates K1.
- Answer: 32 molecules of DNA would be after four PCR if the initial reaction mixture contained two molecules
- After 'n' rounds of the polymerase chain reaction, it is feasible to produce 2 n DNA molecules from a single DNA template molecule (PCR). Therefore, 2 to the power 4 = 16 DNA molecules will be produced after 4 PCR cycles
- If two molecules are doubled four times, 32 DNA molecules are created.
Explanation:
The PCR method is what?
The highly sensitive PCR method enables quick DNA amplification of a particular section. Using visual methods based on size and charge, PCR may detect and identify gene sequences by producing billions of copies of a certain DNA fragment or gene.
What does a PCR have to accomplish?
A given DNA segment can be quickly multiplied (amplified) into millions or billions of copies using the polymerase chain reaction (abbreviated PCR), allowing for more in-depth analysis.
What are the three main PCR steps?
For any DNA synthesis reaction, there are only three easy stages that must be completed: First, the template is denaturated into single strands. Next, primers are annealed to each original strand to synthesise new DNA strands. Finally, the new DNA strands are extended from the primers.
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The answer is the equilibrium concentrations or pressures of each species that occurs in the equilibrium expression, or enough information to determine them. These values are substitued into the equilibrium expression and the value of the equilibrium constant is then calculated.
The correct answer to this question is B. Some members of the Fugate family had a genetic condition called methemoglobinemia, that gave a blue color to their skin. The gene causing this disease is an autosomal recessive gene, so to have this condition you need to be homozygotes for this recessive gene. Gene flow was prevalent in the Fugate family since not all of the children had blue complexion, but only four of them. The three children that did not have blue complexion, had the dominant allele, probably through gene migration from another population nearby. Also, since it is easier nowadays to travel, two separate populations could meet more easily. This increases the incidence of gene flow and explains the reduction of the occurrence of the condition.
