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11111nata11111 [884]
3 years ago
8

Can you help me with this oroblem

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0

Answer:

the picture is not clear.

pls edit


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Use the distance formula, to calculate the ratio of a side length on DEF to the corresponding side length on ABC . Show your wor
wolverine [178]

Step-by-step explanation:

this is the exact answer!!

5 0
3 years ago
Find value of x and y
marshall27 [118]

Answer:

x = 17\sqrt{3}, y = 34

Step-by-step explanation:

Since the triangle is right use trig ratios to find x and y

note exact values sin30° = \frac{1}{2}, tan30° = \frac{1}{\sqrt{3} }

sin30° = \frac{opposite}{hypotenuse} = \frac{17}{y}

multiply both sides by y

y sin30° = 17 ( divide both sides by sin30° )

y = \frac{17}{\frac{1}{2} } = 34

tan30° = \frac{opposite}{adjacent} = \frac{17}{x}

multiply both sides by x

x tan30° = 17 ( divide both sides by tan30° )

x = \frac{17}{\frac{1}{\sqrt{3} } } = 17\sqrt{3}

8 0
3 years ago
How many 1 degree are in 4/360 of a circle
Grace [21]

Answer:

4 degrees.

Step-by-step explanation:

A complete circle has 360 degrees.

(4/360) of a circle =  (4/360) * 360 degrees = 4 degrees

8 0
3 years ago
The Sugar Sweet Company is going to transport sugar to market. It will cost $2600 to rent trucks, and cast an additional 100 for
allochka39001 [22]

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26.00

Step-by-step explanation:

3 0
3 years ago
M is the midpoint of AN, A has coordinates
maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

<u>Figure</u><u> </u><u>:</u><u>-</u>

\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$}   \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg)  \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}

8 0
3 years ago
Read 2 more answers
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