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11111nata11111 [884]
3 years ago
8

Can you help me with this oroblem

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0

Answer:

the picture is not clear.

pls edit


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Find two positive consecutive integers whose product is 132.
iren2701 [21]
If x is the first integer, then x+1 is the second. x(x+1)=132 or x^2+x-132=0. This factors as (x-11)(x+12)=0. Thus either x=11 or x=-12 
<span>So either 11 and 12 or -12 and -11 will do.</span>
7 0
3 years ago
Please help with this ASAP
uranmaximum [27]

Answer:

7w^3/5v

Step-by-step explanation:

42v^3w^4/30v^4w

42 = 6 * 7

30 = 6*5 , factor

6*7v^3w^4/6*5v^4w

6 is common, cancel

7v^3w^4/5v^4w

simplify w^4/w = w^3

v^3/v^4 = 1/v

therefore, 7w^3/5v is the answer

7 0
2 years ago
the coordinates of a pentagon ABCDE are A(-5,4),B (1,4),C(1,-1), D(-2,-5) and E(-5,-1) what is the perimeter of the pentagon
kogti [31]
Perimeter is a continuous line forming the boundary of a closed geometrical figure. perimeter of a pentagon = AB+BC+CD+DE+EA (that is 5 sided figure) 
so my plan is easy but effective, calculate all those distances using those coordinates with the aid of distance formular. then you add those distances algebraically .
7 0
3 years ago
Read 2 more answers
What are the steps on finding common denominators. PLEASE HELP
Dmitrij [34]

Step-by-step explanation:

to find a common denominator, you have to find a number that "works" with every other number.

for example, say you have

2/4 and 8/12

First you need to find the common factor between 4 and 12, so list all your fours

4, 8, 12, 16, 20

Now list all your twelves

12, 24, 36, 48, 60

to find the common factor you look at both your list of numbers and find one that's the same, sometimes it takes a long list of numbers to find the common factor, but you will run into one.

So by looking at our list we see that 4 and 12 share the common factor of 12. but since 8/12 already has a denominator of 12, we are going to leave it alone.

now think about what you would multiply 4 by, to get to 12. The answer is

4 x 3 = 12

to make the numerator correct, you multiply it by the same number you did 4, so since your faction is 2/4 you should do 2 x 3 = 6

now you have your answer,

2/4 and 8/12 turns into

6/12 and 8/12

and that's how you find it, let me know if you have questions :)

7 0
2 years ago
UNA POBLACION DE CIERTA CIUDAD EN EL AÑO 2000 ERA DE 250,000 HABITANTES CON UNA TASA DE CRECIMIENTO RELATIVO DEL 2% , DETERMINA
Fofino [41]

Answer:

La población que se espera para el 2012, es 317,060

Step-by-step explanation:

Si la población tiene un crecimiento relativo del 2%, entonces cada año, la población es un 2% más grande que el año anterior.

Definamos P(t) = población después de t años

Entonces, si al año t = 0 (que corresponde con el año 2000) la población es A

P(0) = A

Un año después, en t = 1, la población incrementa en un 2%

P(1) = A + (2%/100%)*A = A + (0.02)*A = A*(1.02)

Otro año después, en t = 2, la población incrementa un 2% de vuelta.

P(2) = A*(1.02) + (2%/100%)*A(1.02) = A*(1.02) + 0.02*A*(1.02)

      = A*(1.02)*(1.02) = A*(1.02)^2

Ya podemos notar un patrón, la población en el año t va a ser:

P(t) = A*(1.02)^t

Sabemos que en t = 0 (el año 2000) la población es 250,000

Entonces A = 250,000

P(t) = 250,000*(1.02)^t

Ahora queremos calcular la población en el año 2012

entonces si t = 0 es el 2000

2012 esta representado con t = 12

Reemplazando eso en la ecuación, obtenemos:

P(12) = 250,000*(1.02)^12 = 317,060.4

Como esto es una población tenemos que redondearlo al próximo número entero, como el primer digito después del punto es 4, redondeamos para abajo.

Entonces la población que se espera para el 2012 es: 317,060

5 0
2 years ago
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