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konstantin123 [22]
3 years ago
12

She use 17 1 4 cups of sugar and needs another 7 8 cups for other batch how many cups will she use alltogether

Mathematics
1 answer:
kvasek [131]3 years ago
6 0
What you want to do is find the greatest common denominator, so for now put the 17 to the side and focus on the 1/4 and 7/8, we can find the GCD (greatest common denominator) by multiplying 1/4 • 8/8 = 8/32 And then multiplying 7/8 • 4/4 = 28/ 32 So here we have remaining 17 & 8/32 cups PLUS 28/32 cups, you can add the numerators straight across and keeps the denominators the same, which says that she uses 18 & 4/32
Simplified version: 18 & 1/8
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What is the y cordinate of the solution<br>solve 8 and 9<br>​
Flauer [41]

Answer:

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9) Average of change from x = 2 to x = 4: 11

Step-by-step explanation:

8)

y = 2x + 2

y = x^2 + 3

So

x^2 + 3 = 2x + 2

x^2 - 2x + 3 - 2 = 0

x^2 - 2x + 1 = 0

(x - 1)^2 = 0

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x = 1

Plug in x = 1 into either those 2 equations to find y

y = 2(1) + 2 = 4

or

y = (1)^2 +  3 = 1 + 3 = 4

Answer:

The y coordinate of the solution is 4

9)

p(x) = x^2 + 5x - 2

p(2) = 2^2 + 5(2) - 2 = 4 + 10 - 2 = 12

p(4) = 4^2 + 5(4) - 2 = 16 + 20 - 2 = 34

Average of change from x = 2 to x = 4:

[p(4) - p(2)]/[(x(4) - x(2)] = (34 - 12)/(4-2) = 22 /2 = 11

Answer:

Average of change from x = 2 to x = 4 :11

4 0
3 years ago
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zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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