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11Alexandr11 [23.1K]
3 years ago
8

PLEASE HELP ME I NEED HELP ASAP!!!! PLEASE HELP ON A AND B

Mathematics
1 answer:
valina [46]3 years ago
8 0

Answer:

<h2>a) x = 16 and y = 6</h2><h2>b) P = 864 in</h2>

Step-by-step explanation:

a)

The opposite sides of the rectangle are of equal length.

Therefore we have the system of equations:

\left\{\begin{array}{ccc}3y=2+x&\text{subtract 2 from both sides}\\3x=2+x+5y&\text{subtract x from both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}3y-2=x&(*)\\2x=2+5y&(**)\end{array}\right

Substitute from (*) to (**):

2(3y-2)=2+5y\qquad\text{use distributive property}\\\\(2)(3y)+(2)(-2)=2+5y\\\\6y-4=2+5y\qquad\text{add 4 to both sides}\\\\6y=6+5y\qquad\text{subtract 5y from both sides}\\\\\boxed{y=6}

Put the value of y to (*):

x=3(6)-2\\\\x=18-2\\\\\boxed{x=16}

b)

Calculate the width and the length:

3x = 3(16) = 48\\\\3y = 3(6) = 18

The perimeter:

P = 2w + 2l\\\\P = (48)(18)=864\ in

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How many unique triangles can be formed with two side lengths of 10 centimeters and one 40° angle?
r-ruslan [8.4K]

Answer:

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Step-by-step explanation:

Given two sides of 10 cm and one 40° angle

<u>If we use these, we'll get isosceles triangle with:</u>

1. Included 40° angle.

<u>Then the other angles will be same and measure:</u>

  • (180° - 40°)/2 = 70°

2. Adjacent 40° angle. Then one of the angles must be 40° angle as opposite of 10 cm sides.

<u>The remaining angle will measure:</u>

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There no more unique triangles possible, so the answer is two.

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