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3 years ago

Can someone help me ASAP!!!!

Mathematics

1 answer:

erica [24]3 years ago

3 0

Left side I think is A is 12 sandcastles and B is 20 sandcastles.

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4x-5(x-2)=12x+4-x ??????????????

Anestetic [448]

4x - 5(x - 2) = 12x + 4 - x
4x - 5(x) - 5(-2) = 12 - x + 4
 4x - 5x + 10 = 11x + 4
 -x + 10 = 11x + 4
 + x + x 
 10 = 12x + 4
 - 4 - 4
 6 = 12x
 12 12
 0.5 = x

6 0

3 years ago

Reduce 12/20 to lowest term

skelet666 [1.2K]

Answer:

3/5

Step-by-step explanation:

12/20

(divide both by 2)

12/2= 6

20/2=10

6/10

(divide by both by 2)

6/2= 3

10/2= 5

3/5

7 0

3 years ago

if there are 12 dogs that sell for $104 and 8 cats that sell for $25. At the end of the day there are 4 dogs left and 5 cats lef

Vinil7 [7]

Initially there were 12 dogs

dogs left at the end of day =4

number of dogs sold=12-4=8

price of one dog=$104

price of 8 dogs = 104*8= $832

initially there were 8 cats

cats left at the end of day =5

number of cats sold =8-5=3

price of one cat= $25

price of 3 cats =25*3= $75

ratio of sales for dogs to cats = 832/75

7 0

3 years ago

⚡️⚡️Really need help, would appreciate it⚡️⚡️

pentagon [3]

Answer:

The answer to your question is letter A. Regular size is cheaper than Economy size by $0.0003 per gram

Step-by-step explanation:

Cost of 1 gr of economy size

5000 gr (5 kg) ------------------- $ 5.15

1 gr -------------------- X

x = 1 x 5.15 / 5000 = $0.0010

Cost of 1 gr of regular size

820 gr ------------------- $0.60

1 gr -------------------- x

x = 1 x 0.6 / 820 = $ 0.0007

Difference of cost = $0.0010 - $0.0007 = $0.0003

3 0

3 years ago

Find a fraction equivalent to 5/7 whose squared terms add up to 1184.

bogdanovich [222]

The system of equations of two unknowns is formulated and solved.

$\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left\{\begin{matrix} \ \ \ \dfrac{x}{y} = \dfrac{5}{7} \\ x^2+y^2 = 1184 \end{matrix}\right. \ \Longrightarrow \ x=\dfrac{5}{7}y } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left (\dfrac{5}{7}y \right )^2+y^2=1184\ \Longrightarrow\ 25y^2+49y^2=58016 } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{74y^{2}=58016} \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ \ y^{2}=784 } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ y=\pm\sqrt{784}=\pm28 } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{ x=\dfrac{5}{7}(\pm 28)=\pm 20 } \end{gathered}$}$

The fraction that satisfies the request is $\bf{\dfrac{20}{28}}$ , since in $\bf{\dfrac{-20}{-28}}$ the negative signs are canceled and the first fraction is obtained.

3 0

2 years ago