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Arlecino [84]
3 years ago
12

Find the value of x and y.

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
3 0
X is equal to 100 and Y is equal to 16
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How do I solve this equation?
Gnom [1K]

2x(4-x)^{-1/2}-3(4-x)^{1/2}=(4-x)^{-1/2}\bigg(2x-3(4-x)\bigg)

We effectively rewrite the equation as

\dfrac{5x-12}{(4-x)^{1/2}}=0

In order for the LHS to be defined, we need to restrict 4-x>0, or x. Now, the LHS will vanish when the numerator is 0, which happens for

5x-12=0\implies5x=12\implies x=\dfrac{12}5

This value is indeed smaller than 4, so the solution is x=\dfrac{12}5.

8 0
3 years ago
I need help plzz!! Just box number 4, TY
nydimaria [60]

12.36% I think sorry if its wrong ;-;


3 0
3 years ago
Evaluate the following expression when x = -5 and y = 25.
antoniya [11.8K]

Answer:

5

Step-by-step explanation:

5÷5x and 25÷5

1 × 5

your answer is 5

8 0
3 years ago
PLEASEEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPPPPPPPPP
ch4aika [34]

Answer:

-\dfrac{3}{5}

Step-by-step explanation:

1. Find the numerator:

\dfrac{1}{3}-\dfrac{5}{6}=\dfrac{1\cdot 2}{3\cdot 2}-\dfrac{5}{6}=\dfrac{2}{6}-\dfrac{5}{6}=\dfrac{2-5}{6}=-\dfrac{3}{6}=-\dfrac{1}{2}.

2. Simplify the fraction:

\dfrac{-\frac{1}{2}}{\frac{5}{6}}=-\dfrac{1}{2}\cdot \dfrac{6}{5}=-\dfrac{3}{5}.

7 0
3 years ago
How do you find the amplitude of a sine or cosine wave
avanturin [10]
Let's start with the basic sine function<span>, f(t) = </span>sin<span>(t). This </span>function<span> has an amplitude of 1 because the graph goes one unit up and one unit down from the midline of the graph. This </span>function<span> has a </span>period<span> of 2π because the </span>sine<span> wave repeats every 2π units</span>
7 0
3 years ago
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