How do you graph 3.75 on a number line in between 3 and 4
2 answers:
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Answer:
Option b is correct 175
Step-by-step explanation:
n = 7
k = 6
3k -2 ------1
put k = 6 in above eq. for finding first term
a1 = 3(6) - 2 = 18 - 2 = 16
put k = 7 in above eq. for finding first term
a2 = 3(7) - 2 = 21 - 2 = 19
a3 = 3 (8) - 2 = 24 - 2 = 22
16, 19 , 22, ... //Arithmetic series formation
a1 = 16 , a2 = 19
d = a2 - a1 = 19 - 16 = 3 //Difference of first two terms
Using sum forumula for arithmetic series
sum =
=
=
=
=
= 7 * 25
= 175
Answer:
y = -1 and u = 3.333
Step-by-step explanation:
The given equations are :
3u + y = 9 ...(1)
3u-5y = 15 ...(2)
Subtract equation (2) from (1).
3u + y-( 3u-5y)= 9 -15
y+5y = -6
6y = -6
y = -1
Put the value of y in equation (1).
3u + (-1) = 9
3u-1 = 9
3u = 10
u = 10/3
u = 3.333
The attached figure shows the graph for the above equations.
