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lapo4ka [179]
4 years ago
11

Twice one number is 15 less than a second number. when 13 is added to the second number,the result is 7 less than 9 times the fi

rst number
Mathematics
1 answer:
inna [77]4 years ago
8 0
Anwser is 15 beacuse i got the anwser right now

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write an equation of the line passing through point p that is perpendicular to the given line p(6,10),y=-3x+13
patriot [66]

Answer:

y = \frac{1}{3} x + 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - 3x + 13 is in this form

with m = - 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-3} = \frac{1}{3}

y = \frac{1}{3} x + c ← is the partial equation

To find c substitute (6, 10) into the partial equation

10 = 2 + c ⇒ c = 10 - 2 = 8

y = \frac{1}{3} x + 8 ← equation of line


6 0
3 years ago
Ariel buys 2 fish tanks at the pet store. Each
givi [52]

Answer:

19.4 liters

Step-by-step explanation:

You get 19.4 by multiplying 9.7 by 2 which = 19.4

8 0
3 years ago
Read 2 more answers
Can I have help I am stuck on this problem It would mean the world if u helped me and tysm!! =-)
Leona [35]
Answer : 424.875 miles

The problem states that Brian can travel ‘27.5’ miles per gallon, and his tank can only hold ‘15.45’ gallons of fuel.

To find the miles he can travel, all you have to do is multiply the miles he can travel per gallon (27.5) by the gallons he has in the tank (15.45).

This gives you the answer of 424.875 miles.
4 0
2 years ago
Read 2 more answers
Can someone PLEASE help me with Trigonometry???
Svetach [21]
\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}

but anyway, the numerator will give the angles, and θ is just half of each

\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there
7 0
3 years ago
Can someone do my math homework for me please? it's due tomorrow
belka [17]
What’s the question?
6 0
3 years ago
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