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Alex17521 [72]
2 years ago
8

Help someone if you not sleep please

Mathematics
1 answer:
mart [117]2 years ago
8 0

Hello from MrBillDoesMath!

Answer:

+\- 10i

Discussion:

Fortunately, I can do this one in my sleep...... );


+\- sqrt(-100)  =

+\- 10 i                         where i = sqrt(-1)


Thank you,

MrB

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Use a ruler and a protractor to make an
SCORPION-xisa [38]

Answer:

4.891

its side b (opposite side of the 50 degree angle)

Step-by-step explanation:

side c = 6

angle A is 20 side a (opposite side) = 2.184

angle B is 50 side b (opposite side) = 4.891

angle C is 110 side c (opposite side) = 6

1.

get third angle

50 + 20 = 70

180 - 70 = 110

third angle C is 110

2.

get side a

sin A/a = sin C/c

a/c = sinA/sinC

a = c * sinA/sinC

a = 6 * (sin20/sin110)

get sin in degrees

a = 6 * (.342/.9397)

a = 2.184

5 0
1 year ago
2. through: (8,5), perpendicular to y=-1/2x +4
SCORPION-xisa [38]
Perpendicular slope: flip sign and reciprocal = 2
Y = 2x + b
Plug in point (8,5)
5 = 2(8) + b
5 = 16 + b
b = -11
Equation: y= 2x - 11
7 0
3 years ago
SEE ATTACHED
fenix001 [56]
To me personally, the first bit f(g(x)) is easy and the domain is tricky. Let's try explain this.

A function takes an input number and returns an output number depending on the function. Look at f(x) = x+3, if we let the input number be 2 then we say that f(2) = 5. We could do f(π) to give us π+3 or even f(x²) to give us x² +3. The trick is to substitute the input into the function equation.

You have been asked to find f(g(x)). You know f(x) = \frac{1+x}{1-x}. Putting numbers in at this point would be easy (try work out f(2), you'll do it really quick) but you have to put in g(x).

f(g(x)) = \frac{1+g(x)}{1-g(x)}
we also know that g(x) = \frac{x}{1-x} so we can say that
f(g(x)) = \frac{1+ \frac{x}{1-x} }{1- \frac{x}{1-x} } and that is f(g(x)) but the question requires that we simplify it so
\frac{1+ \frac{x}{1-x} }{1- \frac{x}{1-x} }  =  \frac{ \frac{1-x}{1-x} +  \frac{x}{1-x} }{ \frac{1-x}{1-x} - \frac{x}{1-x} } =  \frac{ \frac{1}{1-x} }{ \frac{1-2x}{1-x} } =  \frac{1}{1-2x}

f(g(x)) = \frac{1}{1-2x}

Now for the tricky bit (for me, at least). The domain is the full set of values that you can 'put in to' the function and still get a real value out. So how do we work out what numbers 'break' the function? I like to use the fact that DIVIDING BY ZERO IS IMPOSSIBLE. What value of x can we put into the function to make it so the function is being divided by 0? i.e. 1-2x = 0 solve that and you have a value of x that isn't part of the domain.

This means the domain is all real numbers EXCEPT the solution to that equation. (Because if we put that value into f(g(x)) it's impossible to get a value out.)

[I know this was a lot to read, if you have any questions or don't get anything feel free to message me or leave a comment.]

5 0
3 years ago
Ishan and Hazel plan to retire at age 60 with a retirement income of $48,000 a year from their savings. Rather than pay themselv
GuDViN [60]

Answer:

5

Step-by-step explanation:

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2 years ago
An antelope can run at a speed of 61 miles per hour. What is the speed in yards per second
jekas [21]
0.489 yards per second
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3 years ago
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